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Alex787 [66]
1 year ago
7

One of the waste products produced by kidneys is creatinine. A healthy range ofcreatinine in human blood is between 0.50 mg/dL a

nd 1.1 mg/dL. Elevated levels of thiscompound could indicate a problem with kidney function.The concentration of creatinine in patient’s blood was reported in g/L: 0.0082 g/L.Is this value within the normal range? If it is not, is this concentration low or high?Confirm your answer with your calculations and show all the work.The concentration of creatinine = _____________mg/dL. It is ______________the normal range
Chemistry
1 answer:
Anna35 [415]1 year ago
8 0

The normal range of creatinine in human blood is between 0.50 mg/dL and 1.1 mg/dL. The patient's blood has a concentration of 0.0082 g/L. Let's convert that value into mg/dL.

We kwnot that there are 1000 mg in 1 g. And there are 10 dL in 1 L. We have to use those conversions.

1000 mg = 1 g 10 dL = 1 L

0.0082 g/L = 0.0082 g/L * 1000 mg/g = 8.2 mg/L * 1 L/ (10 dL) = 0.82 mg/dL

0.0082 g/L = 0.82 mg/dL

0.50 mg/dL < 0.82 mg/dL < 1.1 mg/dL

Answer: The concentration of creatinine = 0.82 mg/dL. It is in the normal range.

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C2F4 effuses through a barrier at a rate of 4.6x10-6 mol/hour, while an unknown gas effuses at a rate of 5.8x10-6 mol/hour. What
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The  molar mass  of  the unknown  compound  is   calculated   as   follows

let the unknown  gas be represented by   letter  Y

Rate of C2F4/  rate of  Y  = sqrt of   molar  mass of gas Y/ molar mass of  C2F4

 =  (4.6  x10^-6/ 5.8  x10^-6)  = sqrt  of  Y/ 100

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3 years ago
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Korolek [52]

The volume of the balloon is approximately 2652 liters.

<h3>How to determine the volume occupied by the gas in a balloon </h3>

Let suppose that <em>flammable</em> hydrogen behaves ideally. GIven the molar mass (M), in kilograms per kilomole, and mass of the gas (m), in kilograms. The volume occupied by the gas (V), in cubic centimeters, is found by the equation of state for <em>ideal</em> gases:

V = \frac{m\cdot R_{u}\cdot T}{P\cdot M}   (1)

Where:

  • R_{u} - Ideal gas constant, in kilopascal-cubic meters per kilomole-Kelvin.
  • T - Temperature, in Kelvin
  • P - Pressure, in kilopascals

If we know that m = 0.239\,kg, R_{u} = 8.314\,\frac{kPa\cdot m^{3}}{kmol\cdot K}, T = 273.15\,K, P = 101.325\,kPa and M = 2.02\,\frac{kg}{kmol}, then the volume of the balloon is:

V = \frac{(0.239\,kg)\cdot \left(8.314\,\frac{kPa\cdot m^{3}}{kmol\cdot K} \right)\cdot (273.15\,K)}{\left(101.325\,kPa\right)\cdot \left(2.02\,\frac{kg}{kmol} \right)}

V = 2.652\,m^{3} (2652\,L)

The volume of the balloon is approximately 2652 liters. \blacksquare

To learn more on ideal gases, we kindly invite to check this verified question: brainly.com/question/8711877

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