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Alex787 [66]
1 year ago
7

One of the waste products produced by kidneys is creatinine. A healthy range ofcreatinine in human blood is between 0.50 mg/dL a

nd 1.1 mg/dL. Elevated levels of thiscompound could indicate a problem with kidney function.The concentration of creatinine in patient’s blood was reported in g/L: 0.0082 g/L.Is this value within the normal range? If it is not, is this concentration low or high?Confirm your answer with your calculations and show all the work.The concentration of creatinine = _____________mg/dL. It is ______________the normal range
Chemistry
1 answer:
Anna35 [415]1 year ago
8 0

The normal range of creatinine in human blood is between 0.50 mg/dL and 1.1 mg/dL. The patient's blood has a concentration of 0.0082 g/L. Let's convert that value into mg/dL.

We kwnot that there are 1000 mg in 1 g. And there are 10 dL in 1 L. We have to use those conversions.

1000 mg = 1 g 10 dL = 1 L

0.0082 g/L = 0.0082 g/L * 1000 mg/g = 8.2 mg/L * 1 L/ (10 dL) = 0.82 mg/dL

0.0082 g/L = 0.82 mg/dL

0.50 mg/dL < 0.82 mg/dL < 1.1 mg/dL

Answer: The concentration of creatinine = 0.82 mg/dL. It is in the normal range.

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What is the half-life of 20 g of a radioactive sample if 5 g remain after 8 minutes?
Anni [7]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 20 g

m (final mass after time T) = 5 g

x (number of periods elapsed) = ?

P (Half-life) = ? (in minutes)

T (Elapsed time for sample reduction) = 8 minutes

Let's find the number of periods elapsed (x), let us see:

m =  \dfrac{m_o}{2^x}

5 =  \dfrac{20}{2^x}

2^x = \dfrac{20}{5}

2^x = 4

2^x = 2^2

\boxed{x = 2}


Now, let's find the half-life (P) of the radioactive sample, let's see:

T = x*P

8 = 2*P

2\:P = 8

P = \dfrac{8}{2}

\boxed{\boxed{P = 4\:minutes}}\Longleftarrow(Half-Life)\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

5 0
3 years ago
A bottle of wine contains 9.81 grams of C2H5OH, dissolved in 87.5 grams of water. The final volume of the solution is 100.0 mL.
dimulka [17.4K]

Answer:

[EtOH] = 2.2M and Wt% EtOH = 10.1% (w/w)

Explanation:

1. Molarity = moles solute / Volume solution in Liters

=> moles solute = mass solute / formula weight of solute = 9.8g/46g·mol⁻¹ = 0.213mol EtOH

=> volume of solution (assuming density of final solution is 1.0g/ml) ...

volume solution =  9.81gEtOH + 87.5gH₂O = 97.31g solution x 1g/ml = 97.31ml = 0.09731 Liter solution

Concentration (Molarity) = moles/Liters = 0.213mol/0.09731L = 2.2M in EtOH

2. Weight Percent EtOH in solution (assuming density of final solution is 1.0g/ml)

From part 1 => [EtOH] = 2.2M in EtOH = 2.2moles EtOH/1.0L soln

= {(2.2mol)(46g/mol)]/1000g soln] x 100% = 10.1% (w/w) in EtOH.

3 0
3 years ago
The energy produced when nucleons fuse together is called the: Select the correct answer below:
saveliy_v [14]

Answer:

Option C (nuclear binding energy) is the appropriate choice.

Explanation:

  • At either the nuclear scale, the nuclear binding energy seems to be the energy needed to remove and replace a structure of the atom itself into the characterize elements (to counteract the intense nuclear arsenal).
  • Nuclear warheads (bargaining power) bind everything together neutrons as well as protons within an elementary particle.

Some other options in question aren't relevant to the particular instance. So that the option preceding will also be the right one.

7 0
3 years ago
Name two ways adding salt to lower the freezing temperature benefits you.
miss Akunina [59]

Answer:

Explanation:

Lowers freezing point

3 0
3 years ago
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I believes you would use grams to describe the mass of a tablespoon an you should report that guy
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