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3 years ago

How does lowering Kinetic Energy affect the collision of particles?

Chemistry

1 answer:

uranmaximum [27]3 years ago

8 0

Answer:

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Explanation:

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Why does a year consist of 365 days and a day of 24 hours?

poizon [28]

A year, 365 days, is the time it takes for the Earth to travel around the Sun. A day, 24 hours, is the time it takes for the Earth to spin around once on its axis.

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3 years ago

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The illustration above depicts a spring being compressed and then released. Changes in both potential and kinetic energy occur

Anestetic [448]

Answer:

the potential energy is increasing through steps A & B, then decreases at C.

Explanation:

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3 years ago

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Name two "Storage Polysaccharides" and two "Structural Polysaccharides"

Vsevolod [243]

Answer:

Examples of storage polysaccharides - starch and glycogen and structural polysaccharides - cellulose and chitin

Explanation:

Polysaccharides are the complex carbohydrate polymers, composed of monosaccharide units that are joined together by glycosidic bond.

In other words, polysaccharides are the carbohydrate molecules that give monosaccharides or oligosaccharides on hydrolysis.

The examples of storage polysaccharides are starch and glycogen. The examples of structural polysaccharides are cellulose and chitin.

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3 years ago

The stopcock connecting a 3.06 L bulb containing methane gas at a pressure of 9.61 atm, and a 6.65 L bulb containing oxygen gas

Contact [7]

Answer : The final pressure in the system is 4.22 atm.

Explanation :

First we have to calculate the moles of methane.

$PV=n_1RT$

where,

P = pressure of gas = 9.61 atm

V = volume of gas = 3.06 L

T = temperature of gas = T

$n_1$ = number of moles of methane gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$(9.61atm)\times (3.06L)=n_1\times RT$

$n_1=\frac{29.4}{RT}$

Now we have to calculate the moles of oxygen gas.

$PV=n_2RT$

where,

P = pressure of gas = 1.75 atm

V = volume of gas = 6.65 L

T = temperature of gas = T

$n_2$ = number of moles of oxygen gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$(1.75atm)\times (6.65L)=n_2\times RT$

$n_2=\frac{11.6}{RT}$

Now we have to determine the final pressure in the system after mixing the gases.

$P_{total}=(n_1+n_2)\times \frac{RT}{V_{total}}$

where,

$P_{total}$ = final pressure of gas = ?

$V_{total}$ = final volume of gas = (3.06 + 6.65)L = 9.71 L

T = temperature of gas = T

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$P_{total}=(\frac{29.4}{RT}+\frac{11.6}{RT})\times \frac{RT}{9.71L}$

$P_{total}=4.22atm$

Therefore, the final pressure in the system is 4.22 atm.

4 0

3 years ago

Which of these describes how heat is transfenned by conduction

beks73 [17]

I believe the answer is A. please let me know if i am correct or not.

7 0

4 years ago