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k0ka [10]
3 years ago
11

Electron configurations are a shorthand form of an orbital diagram, describing which orbitals are occupied for a given element.

For example, 1s22s22p1 is the electron configuration of boron. Use this tool to generate the electron configuration of arsenic (As).
Chemistry
2 answers:
andreev551 [17]3 years ago
5 0

Answer:

[Ar] 4s² 3d¹⁰ 4p³

Explanation:

Arsenic has an atomic number of 33, thus 33 protons and 33 electrons. The electron configuration is:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p³

The shorthand notation includes the previous noble gas to represent the inner electrons. The gas previous to arsenic is argon, with 18 electrons. The shorthand notation for arsenic is:

[Ar] 4s² 3d¹⁰ 4p³

kipiarov [429]3 years ago
3 0

Answer:

[Ar] 3d10 4s2 4p3 is shorthand, 1s22s22p63s23p63d104s24p3 long hang

Explanation:

The shorthand is made using the lowest & closest noble gas, and picking up where it leaves off as follows, and longhand is made from a followed pattern you can easily find

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A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o
Ostrovityanka [42]

Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }

where,

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Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

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Aleks04 [339]
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