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rjkz [21]
3 years ago
7

True or False: The domain is the input and x-values of a function table.

Mathematics
2 answers:
S_A_V [24]3 years ago
3 0

Answer:

True

The domain is the input and the range is the output.

mixas84 [53]3 years ago
3 0
The answer :

True



This is because (x,y) where the domain is the input
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Two adjacent sides of a parallelogram are 6mm and 10mm respectively, and they form an angle measuring 60. Find the area of the p
Snowcat [4.5K]

Answer:

51.96 mm² approximately

Step-by-step explanation:

the first thing you should know is that the area of a rectangle is base*height sin of (

the included angle i.e

Arectangle= bh sin90° since all angles of a rectangle are equal then the included angle is 90°

<em>Arectangle= bh sin90° since sin90 is 1 we simply use the equation bh because multiplying bh by one is bh. bearing this in mind , the area of the parallelogram can be calculated as:</em>

Aparallelogram= bh sin of sin of the included angle

Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°

Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866

Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866Aparallelogram=51.96 mm² approximately

4 0
2 years ago
Round<br> 38.86 to 1 decimal place
Sonbull [250]
38.9 is the answer. because it is rounded to the nearest tenth.
5 0
2 years ago
Read 2 more answers
Find the area of the triangle. A drawing of a triangle with base of 18 inches and height of 7 inches. The area is square inches.
Citrus2011 [14]

Answer:

63

Step-by-step explanation:

First we multiply :)

18 x 7 = 126

Now we divide :)

126/2 = 63

Therefore your answer will be 63. :)

Have an amazing day!!

Please rate and mark brainliest!!

3 0
2 years ago
Given right triangle abc and sin A= 1/2, cos A = √3/2
V125BC [204]

Answer:

true

Step-by-step explanation:

sinA² + cosA²=1

⇔(1/2)² + cosA²=1

⇔cosA=±(√3/2)

7 0
3 years ago
Can you always use grouping to factor
Softa [21]

Answer:

No

Step-by-step explanation:

it's not always possible to factor a quadratic expression of this factoring by grouping. The method doesn't work when an expression cannot be factored as (Ax+B)(Cx+D) where A, B, C and D are integrers.

In that case, you should use other methods.

6 0
3 years ago
Read 2 more answers
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