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NeX [460]
3 years ago
8

When balancing a redox reaction, you are balancing

Chemistry
2 answers:
marshall27 [118]3 years ago
5 0
Hope this helped you :)
prisoha [69]3 years ago
4 0

Answer:

D. Both A and C

Explanation:

When balancing a redox equation, you'll first of all check for the oxidation equation, balance the number of moles and then the charges and move next to reduction equation and do the same. Then add up both half-equations to give the overall redox equation. The subscripts on each molecule isn't really required separately since they'll be balanced during the half equations.

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How many grams of ag can be formed from 5.50 grams of ag2o in the equation: 2ag2o (s) → 4ag (s) o2 (g)?
oee [108]

From the given balanced equation we have find out the amount (in gm) of Ag formed from 5.50 gm of Ag₂O.

2Ag₂O(s) → 4Ag (s) + O₂ (g)

We know, molecular mass of Ag₂O= 231.7 g/mol, and atomic mass of Ag= 107.8 g/mol. Given, mass of Ag₂O=5.50 gm. Number moles of Ag₂O=\frac{5.50}{231.7}= 0.0237 moles.

From the balanced chemical reaction we get 2 (two) moles of Ag₂O produces 4 (four) moles of Ag. So, 0.0237 moles of Ag₂O produces \frac{4X0.0237}{2} moles=0.0474 moles of Ag= 0.0474 X 107.8 g of Ag=5.11g Ag.

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3 years ago
What is the molarity of a solution containing 5 moles of HCl in 2.5 L of solution? Be sure to include the formula for calculatin
beks73 [17]

Answer:

\boxed{\text{2 mol/L}}

Step-by-step explanation:

c = \dfrac{ \text{moles} }{ \text{litres}}\\\\c = \dfrac{n }{V }

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V = 2.5 L

Calculation:

c = \dfrac{ \text{5 mol} }{\text{2.5 L}} = \text{2 mol/L}

The molar concentration of the solution is \boxed{\textbf{2 mol/L}}.

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The Gibb's free energy change (ΔG) is:

ΔG<0⟶ Spontaneous process

ΔG>0⟶  Non-spontaneous process

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