Question

for the simple harmonic motion equation d = 9cos(pi/2)(t), what is the maximum displacement from the equilibrium position ?

Answer 1

Answer:

The maximum displacement from the equilibrium position is 9

Step-by-step explanation:

We are given

equation for the simple harmonic motion equation

$y=9cos(\frac{\pi}{2}t)$

we can use trig formula

$y=Acos(Bt)$

The maximum value of this equation is always A

So, firstly, we will compare and find A

A=9

so,

The maximum displacement from the equilibrium position is 9

Answer 2

Answer: 9

Step-by-step explanation:

1. You know that  the simple harmonic motion equation is:

$d=9cos(pi/2)(t)$

2. You have the following trigonometric function of cosine:

$y=acos (b(x-c)+d$

Where a is the amplitude, or the  maximum displacement.

2. Therefore, the maximum displacement from the equilibrium position of the equation given in the problem is 9.