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Kipish [7]
3 years ago
7

Who can help me with this worksheet ASAP need it for my tomorrow and I have a lot of homework to do please someone help me

Mathematics
1 answer:
RUDIKE [14]3 years ago
6 0

Answer:

  1. 5n square root 5
  2. 6 square root 6v
  3. 16ki square root 2
  4. 10m square root m
  5. 4p square root 5p
  6. 3pi square root 5


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What is... y=15x+2100
mrs_skeptik [129]

Y=2100 because you plug in 0 for x. Then you plug in your y value in the equation and solve

5 0
3 years ago
45 POINTS IF ANSWER!!!<br> Find the value of X in the triangle shown below.
pochemuha

Answer:

The bacterium expels oxygen, making room for

hydrogen peroxide and carbon dioxide. These elements are then combined with solar energy to produce fuel.

Step-by-step explanation:

.

.

Thank my answer and mark me as brainist

8 0
2 years ago
Read 2 more answers
5x-2 what’s the slope and y-int ?
uranmaximum [27]

Answer:

Slope = 5.

y-int = (0, -2).

Step-by-step explanation:

y = 5x - 2

The slope intercept form is

y = mx + b  where m = the slope and b = the y-intercept.

So here,  the slope = 5 and the y-intercept is where y = -2.  That is the point (0, -2).

8 0
3 years ago
If vector u = &lt;-3.5, -1.5&gt; and vector v = &lt;-1.25, 2.25&gt;, which graph shows the resulting vector for 2v − u?
Sedaia [141]

Answer:

D

Step-by-step explanation:

We know that vector addition is scalar addition.

Given vectors are u = <-3.5, -1.5> and v = <-1.25, 2.25>

2v = < -2.5, 4.5>

2v - u = < -2.5, 4.5> - <-3.5, -1.5> = < -2.5 - (-3.5) , 4.5 -(-1.5) >

2v-u = < 1 , 6 >

This vector is basically i + 6j which is drawn in option D

8 0
3 years ago
Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sel
GarryVolchara [31]

Answer:

The unusual X values ​​for this model are: X = 0, 1, 2, 7, 8

Step-by-step explanation:

A binomial random variable X represents the number of successes obtained in a repetition of n Bernoulli-type trials with probability of success p. In this particular case, n = 8, and p = 0.53, therefore, the model is {8 \choose x} (0.53) ^ {x} (0.47)^{(8-x)}. So, you have:

P (X = 0) = {8 \choose 0} (0.53) ^ {0} (0.47) ^ {8} = 0.0024

P (X = 1) = {8 \choose 1} (0.53) ^ {1} (0.47) ^ {7} = 0.0215

P (X = 2) = {8 \choose 2} (0.53)^2 (0.47)^6 = 0.0848

P (X = 3) = {8 \choose 3} (0.53) ^ {3} (0.47)^5 = 0.1912

P (X = 4) = {8 \choose 4} (0.53) ^ {4} (0.47)^4} = 0.2695

P (X = 5) = {8 \choose 5} (0.53) ^ {5} (0.47)^3 = 0.2431

P (X = 6) = {8 \choose 6} (0.53) ^ {6} (0.47)^2 = 0.1371

P (X = 7) = {8 \choose 7} (0.53) ^ {7} (0.47)^ {1} = 0.0442

P (X = 8) = {8 \choose 8} (0.53)^{8} (0.47)^{0} = 0.0062

The unusual X values ​​for this model are: X = 0, 1, 7, 8

6 0
3 years ago
Read 2 more answers
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