Slope is rise/run
gains 4m height for every 3secons
rise=4m
run=3sec
slope=4/3
if takes 54seconds t
54 times 4/3=72 meters
max height is 72 meteres assuming that it starts from the ground level
Okay so there are 360 degrees in a circle graph
So 67%*360 degrees =241 degrees
Check the picture below.
so we can say that two sides are "4" each in length, since opposite sides are equal, let's find how long the slanted sides are.
![~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[3 - (-4)]^2 + [5 - 2]^2}\implies d=\sqrt{(3+4)^2+3^2} \\\\\\ d=\sqrt{49+9}\implies d=\sqrt{58} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{4~~ + ~~4~~ + ~~\sqrt{58}~~ + ~~\sqrt{58}\implies 8+2\sqrt{58}}](https://tex.z-dn.net/?f=~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20%28%5Cstackrel%7Bx_1%7D%7B-4%7D~%2C~%5Cstackrel%7By_1%7D%7B2%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B3%7D~%2C~%5Cstackrel%7By_2%7D%7B5%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20d%3D%5Csqrt%7B%5B3%20-%20%28-4%29%5D%5E2%20%2B%20%5B5%20-%202%5D%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B%283%2B4%29%5E2%2B3%5E2%7D%20%5C%5C%5C%5C%5C%5C%20d%3D%5Csqrt%7B49%2B9%7D%5Cimplies%20d%3D%5Csqrt%7B58%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7B%5CLarge%20Perimeter%7D%7D%7B4~~%20%2B%20~~4~~%20%2B%20~~%5Csqrt%7B58%7D~~%20%2B%20~~%5Csqrt%7B58%7D%5Cimplies%208%2B2%5Csqrt%7B58%7D%7D)
Answer:
answer is subtract the 180-120=80
In a table it's EXAMPLE: Cars/Drivers the cars is x and the drivers is y(y-intercept). In an equation, EXAMPLE using y=mx+b the b is the y-int., and in a graph it is (x,y) the y being the y-int.