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Westkost [7]
3 years ago
9

Can someone help me !!

Physics
1 answer:
Leona [35]3 years ago
7 0

Answer:

You are right with the answer you have, I believe!

Yeet

Explanation:

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A conducting sphere of radius 5.0 cm carries a net charge of 7.5 µC. What is the surface charge density on the sphere?
11111nata11111 [884]

Answer:

\sigma=0.014\ C/m^2

Explanation:

Given that,

The radius of sphere, r = 5 cm = 0.05 m

Net charge carries, q = 7.5 µC = 7.5 × 10⁻⁶ C

We need to find the surface charge density on the sphere. Net charge per unit area is called the surface charge density. So,

\sigma=\dfrac{7.5\times 10^{-6}}{\dfrac{4}{3}\pi \times (0.05)^3}\\\\=0.014\ C/m^2

So, the surface charge density on the sphere is 0.014\ C/m^2.

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3 years ago
Which of the following is an example of maintaining homeostasis?
UNO [17]

Answer:

the first answer is correct

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3 years ago
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Explain it if u know please ​
Rudik [331]

Answer: B

Explanation: The straight line shows the theoretical average of the actual velocity  and the curved line show that it is less than the average velocity of the object within 6 seconds.

straight line:

3. 3,80

6. 6,160

curved line:

  1. 1,2
  2. 2,17
  3. 3,32
  4. 4,60
  5. 5,100
  6. 6,160

A.K.A.-- the only place where the straight line and the curved line meet at is only at coordinate 6,160.

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What advantage do weather do weather satellites have over ground based weather stations
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Answer:

Satellites can gather weather data from much higher altitudes than land-based instruments can.

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3 years ago
A 1.2-mol sample of hydrogen gas has a temperature of 21 ∘C.
Strike441 [17]
A) The average translational kinetic energy of the molecules in a gas is given by:
K =  \frac{3}{2}k_B T
where
k_B is the Boltzmann's constant
T is the absolute temperature of the gas

In our problem, T=21.0^{\circ}C +273 = 294 K, so the average translational kinetic energy of the molecules is
K= \frac{3}{2}(1.38 \cdot 10^{-23} J/K)(294 K)=6.09 \cdot 10^{-21} J

We have 1.2 mol of this gas, and since one mole of ideal gas contains a number of molecules equal to Avogadro number, the total number of molecules in our gas is
N=n N_A = (1.2 mol)(6.022 \cdot 10^{23} mol^{-1} ) =7.35 \cdot 10^{23}

So the total translational kinetic energy of all molecules of the gas is
K_{tot}= NK = (7.35 \cdot 10^{23})(6.09 \cdot 10^{21} J)=4476 J = 4.5 \cdot 10^3 J


B) The kinetic energy of a person is given by:
K= \frac{1}{2}mv^2
where m is the person's mass and v his velocity. The person has a mass of m=75 kg and its energy is equal to the energy of the gas, K=4.5 \cdot 10^3 J, therefore his velocity must be
v= \sqrt{ \frac{2K}{m} }= \sqrt{ \frac{2 (4.5 \cdot 10^3 J)}{75 kg} } =11 m/s
4 0
3 years ago
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