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3 years ago

How much time elapses before the two kittens collide

Physics

1 answer:

geniusboy [140]3 years ago

3 0

Answer:

6.8 s

Explanation:

Let's say the west end of the field is position 0 m and the east end of the field is position 250 m.

The position of kitten A is:

x = 0 + 25 t

And the position of kitten B is:

x = 250 - 12 t

The kittens collide when they have the same position:

25 t = 250 - 12 t

37 t = 250

t ≈ 6.8 s

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Thermal resistance for copper ( $R_{c}$ ) = \frac{L_{c}}{k_{c} \times A_{c}}[/tex]

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Putting the given values into the above formula as follows.

Q = $\frac{(100^{o} - 0^{o})}{\frac{L_{I}}{k_{I}.A_{I}} + \frac{L_{c}}{k_{c}.A_{c}}}$

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Here, T is 1 second so, power conducted is equal to heat transferred.

So, P = 2.92 watt

Thus, we can conclude that 2.92 watt power will be conducted through the rod when it reaches steady state.

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