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Tamiku [17]
3 years ago
14

Explain it if u know please ​

Physics
2 answers:
Rudik [331]3 years ago
6 0

Answer: B

Explanation: The straight line shows the theoretical average of the actual velocity  and the curved line show that it is less than the average velocity of the object within 6 seconds.

straight line:

3. 3,80

6. 6,160

curved line:

  1. 1,2
  2. 2,17
  3. 3,32
  4. 4,60
  5. 5,100
  6. 6,160

A.K.A.-- the only place where the straight line and the curved line meet at is only at coordinate 6,160.

CaHeK987 [17]3 years ago
4 0

refer to the attachment!!

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Which law is associated with inertia
N76 [4]

Answer:

The focus of Lesson 1 is Newton's first law of motion - sometimes referred to as the law of inertia. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

4 0
4 years ago
After coming down a slope, a 60-kg skier is coasting northward on a level, snowy surface at a constant 15 m>s. Her 5.0-kg cat
Vinil7 [7]

To solve this exercise, it is necessary to apply the concepts of conservation of the moment especially in objects that experience an inelastic colposition.

They are expressed as,

m_1v_1+m_2v_2 = (m_1+m_2)v_f

Where,

m_1= mass of the skier

m_2= mass of the cat

v_1 = initial velocity of skier

v_2 = initial velocity of cat

v_f= final velocity of both

Re-arrange to find V_f we have,

V_f = \frac{m_1v_1+m_2v_2}{(m_1+m_2)}

V_f = \frac{(60)(15)+(5)(-3.8)}{(60+5)}

V_f = 13.55m/s

Once the final velocity is found it is possible to calculate the change in kinetic energy, so

\Delta KE = KE_i-KE_f

\Delta KE = \frac{1}{2}(m_1v_1^2+m_2v^2_2)-\frac{1}{2}(m_1+m_2)v_f^2

\Delta KE = \frac{1}{2}((60)(15)^2+(5)(-3.8)^2)-\frac{1}{2}(60+5)(13.55)^2

\Delta KE = 819.1J

Therefore the amount of kinetic energy converted in to internal energy is 819J

3 0
3 years ago
Please help homework due tomorrow,,,
Ad libitum [116K]
Cody ...

Everything on this page is solved with the SAME formula !

             Distance = (speed) x (time) .


Before I get into how to solve each problem, we need to notice that
this whole sheet deals with speed, NOT velocity.

'Velocity' is speed AND THE DIRECTION OF THE  MOTION.
Nothing on this page ever mentions direction, so there's no velocity
anywhere on the page.

Your teacher may not be happy if you talk about this on your homework,
but that's too bad.  Just don't say "velocity" in any of your answers.
Say "speed", and if the teacher complains about that, then it's time to
let the teacher have it with both barrels.
 

1).  Speed = (distance covered) / (time to cover the distance)

2).  Speed = (distance covered) / (time to cover the distance)

3).  Distance  =  (average speed of travel) x (time traveling at that speed)

4).  Time to cover the distance = (distance) / (speed)

5).  Car's     speed = (distance the car covered)        / (time the car took)
      Sprinter speed = (distance the sprinter covered) / (time the sprinter took)

      Calculate the car's speed.
      Calculate the sprinter's speed.
     
      ... Look at the two speeds.
          Decide which one is faster.
     
      ... Subtract the slower one from the faster one. 
          The difference is the answer to "by how much?" .

6).  Distance  =  (speed) x (time spent moving at that speed)

7).  Average speed  =  (TOTAL distance covered)
                                      divided by
                                    (time to cover the TOTAL distance).
   

8 0
3 years ago
Suppose a piano tuner hears 2 beats per second when listening to the combined sound from her tuning fork and the piano note bein
maksim [4K]

Answer:

further tightening is required.

Explanation:

The beat created / sec = difference of frequencies

Initial beat heard = 2

so difference of frequencies = 2

after tightening beat heard  = 1

difference  of frequencies decreases because frequency of tuning fork was higher than piano sound.

on further tightening  difference decreases because tightening increases the frequency  of piano hence   further  tightening is required for resonance.

6 0
3 years ago
Which equation is used to calculate the electric potential in an electric field from a point charge? V = kq over d squared V = k
Contact [7]

Answer:

The answer is V =delta U over q

Explanation:

Electric potential is defined as the magnitude of the electric field through the potential energy that a charge would have if placed at that point. Mathematically, the potential is defined with the following expression:

V=\frac{E_{p} }{q}

where:

V is the electric potential. Its unit is Julius by Coulomb (J/C).

Ep is the electric potential energy that has a charge

q is the charge

In the question Ep = ΔU

4 0
3 years ago
Read 2 more answers
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