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3 years ago

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An 8.0-ohm resistor and a 6.0-ohm resistor are connected in series with a battery. The potential difference across the 6.0-ohm r

esistor is measured as 12-V. (a) Find the total resistance of the circuit. (b) Find the current in the 6.0-ohm resistor. (c) Find the potential difference across the battery.
Please show work! :)

1 answer:

ipn [44]3 years ago

6 0

Answer:

a) 14 Ω

b) 2.0 A

c) 28 V

Explanation:

a) The total resistance of resistors in series is the sum:

R = R₁ + R₂

R = 8.0 Ω + 6.0 Ω

R = 14 Ω

b) The current in the 6.0 Ω resistor can be found with Ohm's law:

V = IR

12 V = I (6.0 Ω)

I = 2.0 A

c) Since the resistors are in series, they have the same current. So the total voltage is:

V = IR

V = (2.0 A) (14 Ω)

V = 28 V

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