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malfutka [58]
2 years ago
13

1. Gwen exerts a 16 N horizontal force as she pulls a 32N sled across a cement

Physics
1 answer:
PSYCHO15rus [73]2 years ago
5 0

Answer:

3.6 N   Kinetic friction

Explanation:

3 )   Ff = uk * Fn = 3.6 N

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In the equation for Ohm’s law what does I stand for?
Ket [755]
A) current 

(I is always current in electricity)
3 0
3 years ago
When the tube is filled with mercury vapor, as in this case, a sharp drop in the collected current is observed when the accelera
Nata [24]

Answer:

The energy absorbed by the atomic electrons in the mercury atom is 7.84 \times 10^{-19} J

Explanation:

Given:

Potential V = 4.9 V

According to the conservation law,

   Loss in kinetic energy = Gain in potential energy

Here, energy absorbed by the atomic electrons is given by,

    E = eV

Where e = 1.6 \times 10^{-19} C       ( charge of electron )

    E = 1.6 \times 10^{-19 } \times 4.9

    E = 7.84 \times 10^{-19} J

Therefore, the energy absorbed by the atomic electrons in the mercury atom is 7.84 \times 10^{-19} J

5 0
3 years ago
3. Using the F, m, a triangle, calculate the boy's mass. Use the "force
aliya0001 [1]

Answer: 30kg

Explanation:

F = 300N

m = ?

a = 10 m/s/s

m = f/a = 300N/10 m/s/s

m = 30kg

5 0
3 years ago
The starships of the Solar Federation are marked with the symbol of the Federation, a circle, whereas starships of the Denebian
Llana [10]

Complete question

The complete question is shown on the first uploaded image  

Answer:

The velocity is  v = c* \sqrt{1 -  \frac{1}{n^2} }

Explanation:

From the question we are told that

           a = nb

The length of the minor axis  of  the symbol of the Federation, a circle, seen by the observer at velocity v must be equal to the minor axis(b) of the  Empire's symbol, (an ellipse)

Now this length seen by the observer can be mathematically represented as

        h = t \sqrt{1 - \frac{v^2}{c^2} }

Here t  is the actual length of the major axis of of the  Empire's symbol, (an ellipse)

So t = a = nb

and  b is the length of the minor axis of the symbol of the Federation, (a circle) when seen by an observer at velocity v which from the question must be the length of the minor axis of the of the  Empire's symbol, (an ellipse)

 i.e    h = b

So

    b  =  nb  [\sqrt{1 - \frac{v^2}{c^2} } ]  

     [\frac{1}{n} ]^2 =  1 -  \frac{v^2}{c^2}

      v^2 =c^2 [1- \frac{1}{n^2} ]

       v^2 =c^2 [\frac{n^2 -1}{n^2} ]

        v = c* \sqrt{1 -  \frac{1}{n^2} }

     

     

6 0
3 years ago
In a nuclear fusion reaction two 2H atoms are combined to produce one 4He.
Mrrafil [7]

Answer:

a)= 0.025602u

b) = 23.848MeV

c) N = 1.546 × 10¹³

Explanation:

The reaction is

²₁H   +   ²₁H   ⇄   ⁴₂H + Q

a) The mass difference is

Δm = 2m(²₁H) - m (⁴₂H)

       = 2(2.014102u) - 4.002602u

        = 0.025602u

b) Use the Einstein mass energy relation ship

The enegy  release is the mass difference times 931.5MeV/U

E = (0.025602) (931.5)

   = 23.848MeV

c)

the number of reaction need per seconds is

N = Q/E

     = 59W/ 23.848MeV

  = \frac{59}{(23.848 \times 10^6 )(1.6 \times 10^1^9) } \\\\= 1.546 \times 10^1^3

N = 1.546 × 10¹³

5 0
3 years ago
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