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Nikitich [7]
3 years ago
11

A certain field is a rectangle with a perimeter of 918 feet. The length is 181 feet more than the width. Find the width and leng

th of the rectangular field The width is? feet. The length is ? feet.

Mathematics
1 answer:
hjlf3 years ago
6 0

Answer:

Width: 139 feet

Length: 328 feet

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Geometry Problems.

I have created an illustration to help you better understand the situation and have attached it below. Based on the illustration we can use the formula for the perimeter. We know that the regular formula for the perimeter of a rectangle is

P = 2L+2W

Now we can just plug in the values shown in the illustration.

918 = 2(181+W)+2W .... distribute the 2

918 = 362+2W+2W ... subtract 362 on both sides

556 = 4W ... divide by 4 on both sides

139 = W

Finally, we can see that the value of W is 139 feet. Therefore the value of L is,

L = 189 + 139

L = 328

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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belka [17]

Answer:

\therefore 2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}

Step-by-step explanation:

The question relates to dividing a fraction by proper and another fraction

The given expression is presented as follows;

2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right )

We rearrange the fractions as improper  fractions for easier division as follows;

2\dfrac{1}{3}  = \dfrac{7}{3}

-3\dfrac{2}{3} = -\dfrac{11}{3}

Therefore, we have;

2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = \dfrac{7}{3} \div \left (-\dfrac{11}{3} \right ) = \dfrac{7}{3} \times \left (\dfrac{1}{-\dfrac{11}{3} } \right ) = \dfrac{7}{3} \div \left (-\dfrac{3}{11} \right ) =-\dfrac{7}{11}

\therefore 2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}

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