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Svet_ta [14]
3 years ago
10

Consider the reaction:

Chemistry
1 answer:
Flura [38]3 years ago
5 0

Answer:

2 one is the correct one

Explanation:

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Wood, Iron, Glass, Paper, Nickel Which substances show magnetic property?
____ [38]
If I am correct the answer would be iron and nickel.
4 0
3 years ago
Assume reaction N (g )space plus O (g )rightwards arrow N O (g )occurs in high layers of the atmosphere. What is the H subscript
8090 [49]

Answer:

Kindly check the explanation section.

Explanation:

From the description given in the question above, that is '' H subscript f to the power of degree of the reaction" we have that the description matches what is known as the heat of formation of the reaction, ∆fH° where the 'f' is a subscript.

In order to determine the heat of formation of any of the species in the reaction, the heat of formation of the other species must be known and the value for the heat of reaction, ∆H(rxn) must also be known. Thus, heat of formation can be calculated by using the formula below;

∆H(rxn) = ∆fH°( products) - ∆fH°(reactants).

That is the heat of formation of products minus the heat of formation of the reaction g specie(s).

Say heat of formation for the species is known as N(g) = 472.435kj/mol, O(g) = 0kj/mol and NO = unknown, ∆H°(rxn) = −382.185 kj/mol.

−382.185 = x - 472.435kj/mol = 90.25 kJ/mol

5 0
3 years ago
Calculate the vapor pressure of a solution made by dissolving 109 grams of glucose (molar mass = 180.2 g/mol in 920.0 ml of wate
Fynjy0 [20]
Given data: <span>molar mass = 180.2 g/mol in 920.0 ml of water at 25 °c.
                   </span><span>the vapor pressure of pure water at 25 °c is 23.76 mm hg. 
</span>Asked: <span>the vapor pressure of a solution made by dissolving 109 grams of glucose
</span><span>
Solution:
moles glucose = 109 g/ 180.2 g/mol=0.605 
mass water = 920 mL x 1 g/mL = 920 g 
moles water = 920 g/ 18.02 g/mol=51.1 
mole fraction water = 51.1 / 51.1 + 0.605 =0.988 
vapor pressure solution = 0.988 x 23.76 = 23.47 mm Hg</span>
6 0
4 years ago
6.0 mol NaOH reacts with
kodGreya [7K]

2 moles of Na3PO4 form from 6.0 mol NaOH. Details about stoichiometry can be found below.

<h3>How to calculate number of moles?</h3>

The number of moles of a substance can be calculated stoichiometrically as follows:

3NaOH + H3PO4 → 3H₂O + Na3PO4

According to this equation,

3 moles of NaOH produces 1 mole of Na3PO4

This means that 6 moles of NaOH will produce 6/3 = 2 moles of Na3PO4

Therefore, 2 moles of Na3PO4 form from 6.0 mol NaOH.

Learn more about stoichiometry at: brainly.com/question/9743981

#SPJ1

7 0
2 years ago
The volume of an automobile air bag was 66.8 L when inflated at 25 °C with 77.8 g of nitrogen gas. What was the pressure in the
Ray Of Light [21]

Answer:

\large \boxed{\text{103 kPa}}

Explanation:

We can use the Ideal Gas Law — pV = nRT

Data:

V = 66.8 L

m = 77.8 g

T = 25 °C

Calculations:

(a) Moles of N₂

\text{Moles of N}_{2} = \text{77.8 g N}_{2} \times \dfrac{\text{1 mol N}_{2}}{\text{28.01 g N}_{2}} = \text{2.778 mol N}_{2}

(b) Convert the temperature to kelvins

T = (25 + 273.15) K = 298.15 K

(c) Calculate the pressure

\begin{array}{rcl}pV & =& nRT\\p \times \text{66.8 L} & = & \text{2.778 mol} \times \text{8.314 kPa$\cdot$ L$\cdot$K$^{-1}$mol$^{-1}\times$ 298.15 K}\\66.8p & = & \text{6886 kPa}\\p & = & \textbf{103 kPa}\end{array}\\\text{The pressure in the bag is $\large \boxed{\textbf{103 kPa}}$}

3 0
3 years ago
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