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sergeinik [125]
3 years ago
9

A football player with a mass of 200 kilograms sprints towards the goal line. Another football player with a mass of 120 kilogra

ms accelerating at the same rate runs next to him. Both players tackle the player in the end zone with the football. Which football player applied the most force, and why?
Chemistry
2 answers:
mihalych1998 [28]3 years ago
5 0

Answer:

oh i love football. i know this. The guy with 200 kilograms because he is heavier o that means more weight going against the guy. Is this American football. cause i love American football  

Explanation:

Nimfa-mama [501]3 years ago
5 0
Technically I believe it would be equal because they are going at the same momentum

If the ball carrier and tackler have equal momentum, the forward momentum of the ball carrier is exactly matched by the backward momentum of the tackler. The motion of the two will stop at the point of contact.

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You have dissolved 10 g sodium oxide in 200 ml water.calculate concentration of the solution
e-lub [12.9K]

Answer:

0.85 Molar Na2O

Explanation:

Determine the moles of sodium oxide, Na2O, in 10 grams by dividing by the molar mass of Na2O (61.98 g/mole).

 (10 g Na2O)/(61.98 g/mole) = 0.161 moles Na2O.

Molar is a measure of concentration.  It is defined as moles/liter.  A 1 M  solution contains 1 mole of solute per liter of solvent.  [200 ml water = 0.2 Liters water.]

In this case, we have 0.161 moles Na2O in 0.200 L of solvent.

 (0.161 moles Na2O)/(0.200 L) = 0.85 Molar Na2O

8 0
2 years ago
You add 100.0 g of water at 52.0 °C to 100.0 g of ice at 0.00 °C. Some of the ice melts and cools the water to 0.00 °C. When the
lara31 [8.8K]

Answer:

m_{ice} = 65.336\,g

Explanation:

Accoding to the First Law of Thermodynamics, the heat released by the water melts a portion of ice. That is to say:

Q_{water} = Q_{ice}

(100\,g)\cdot \left(4.184\,\frac{J}{kg\cdot ^{\textdegree}C}\right)\cdot (52\,^{\textdegree}C - 0\,^{\textdegree}C) = m_{ice}\cdot \left(333\,\frac{J}{g} \right)

The amount of ice that is melt is:

m_{ice} = 65.336\,g

5 0
4 years ago
when 32.4 g of water vapor condenses, how much heat is given off? The heat of vaporization for water is 40.67 kj/mol
egoroff_w [7]
When a water vapor condenses, heat is being released from the process. This heat is called latent heat of vaporization since the phase change happens without any change in the temperature. This value is constant per mole of a substance as a function of pressure and temperature. For this problem, we are given the heat of vaporization at a certain T and P. We use this value to calculate the total heat released from the process. We calculate as follows:

Total heat released: 32.4 g ( 1 mol / 18.02 g ) (40.67 kJ / mol) = 73.12 kJ

Therefore, 73.12 kJ of heat is released from the condensation of 32.4 g of water vapor.
3 0
3 years ago
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Agata [3.3K]

B. Cl- has 17 electrons.

7 0
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Some types of bar soap will float in water. What are the dispersed particles?
Sergio039 [100]

Answer:

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Explanation:

3 0
3 years ago
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