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3 years ago

Which description accurately represents a water molecule? (1 point)

2 answers:

7 0

The description which accurately represents a water molecule is slightly negative oxygen pole, slightly positive hydrogen poles.

Water is a polar molecule. This means that the molecule has a dipole moment.

The polarity of water arises from the difference in electronegativity between hydrogen and oxygen.

Hence, in water molecule, oxygen is slightly negative and hydrogen is slightly positive thereby resulting in a dipole.

Learn more: brainly.com/question/10904296

Katyanochek1 [597]3 years ago

7 0

Answer:

Ions in Polar Solvents Quick Check

Explanation:

1. Water dissolves more substances than any other solvent

2. Electron shared between atoms

3. Slightly negative oxygen pole, slightly positive hydrogen poles

4. The electron transfer in ionic compounds results in ions that are attracted to water’s poles.

5. Ionic, yes

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A compound that is composed of only carbon and hydrogen contains 80.0% c and 20.0% h by mass. What is the empirical formula of t

gladu [14]

<u>Solution</u> : Emperical Formula = $CH_{3}$

Emperical Formula - A formula that gives the simplest whole number ratio of atom in a compound.

In the question percentages are given then assume that the total mass is 100grams so that the mass of each element is equal to the percentage given.

Given : 80.0g Carbon

20.0g Hydrogen

First convert the given masses into moles.

$80.0g\text{ C} \times \frac{1 g/mole \text{ C}}{12.0 g/mole \text{ C}}= 6.66\text{mole of C}$

$20.0g\text{ H} \times \frac{1 g/mole \text{ H}}{1 g/mole \text{ H}}= 20.0\text{mole of H}$

Value of each mole divided by the smallest number of moles and then round off.

Moles ratio of the element are

$\frac{6.66}{6.66}\text{mole of C}= 1$

$\frac{20.0}{6.66}\text{mole of C}= 3$

This is the mole ratio of the elements and is repersented by the subscript in the emperical formula.

Emperical Formula = $CH_{3}$

3 0

4 years ago

At constant temperature and pressure, 5.0 L of SO2 is

Ne4ueva [31]

I've done this a few times and keep coming up with 5.0 L . I used the mole ratio, and SO 2 as the LR. That would make 2 moles of SO3 5.0 L but its not one of your choices. the temp and pressure are constant, so according to n/v = p/rt the volume is the same as the moles. hope this helps

4 0

4 years ago

A 5.00 mL of a salt solution of unknown concentration was mixed with 35.0 mL of 0.523 M AgNO3. The mass of AgCl solid formed was

Lapatulllka [165]

Answer:

The chemical term in the equation for the precipitate of AgCl(s) is n=3.54*10^-3

Explanation:

the quantity of AgCl(s) in moles is:

n = 0.508g / 143.32 g/mol = 3.54*10^-3 mol

to verify it the mass of AgNO3 involved in the reaction should be

n AgNO3 required = n = 3.54*10^-3 mol

the mass of n involved should be higher than n AgNO3

n existing = V*N = 0.523 mol/L * 35*10^-3 L = 18.305*10^-3 mol

5 0

4 years ago

Read 2 more answers

Changing the number of protons in an atom makes<br><br> A. an ion<br> B. an isotope

lana [24]

A. an ion

The atom gains a net electrical charge if the number of protons and electrons are not equal which makes it an ion.

5 0

3 years ago

Metal rings can be coated with a layer of copper using electricity.

Eduardwww [97]

<u>First of all, what is electrolysis?</u>

Electrolysis is the process of breaking down ionic substances using direct current.

<u>Important points about electrolysis </u>

→ Ionic substances contain particles called ions.

→ Electricity is the flow of electrons or ions. For electrolysis to work, the compound must contain ions. The ions must be free to move for electrolysis to occur and it can happen by melting or dissolving an ionic substance in water.

→ Positively charged ions move to the negative electrode. They receive electrons and are <em>reduced</em>. The positive ions move towards the negative electrode because they want to cancel each other out.

→ Negatively charged ions move to the positive electrode. They lose electrons and are <em>oxidised</em>. The substance that is broken down is called the electrolyte <em>(an electrolyte is just a liquid or solution that can conduct electricity)</em> . The negative ions move towards the positive electrode because they want to cancel each other out.

<h3>Cathode = Negative electrode</h3><h3>Anode = Positive electrode</h3>

Metal ions form at the cathode and non-metal ions form at the anode

How I remember if an element is <em>oxidised</em> or <em>reduced</em> is by remembering OIL RIG

OIL = Oxidation is Loss (of electrons)

RIG = Reduction is Gain (of electrons)

<h2><em><u>The answer to your question</u></em></h2>

1) The first step would be to clean the metal ring and sand it down because when the metal atoms from the electrolyte are deposited onto the ring, they will form a weak bond and they may simply 'fall' off. Also this could affect conductivity and the whole experiment. The more things you do accurately now, the more accurate your result will be.

2) You want to put the solution you are given in to the tank your going to be using.

3) This is basically the main part, you want to set up the circuit, I have attached a diagram at the bottom to show you the circuit. The copper rod will be the anode and the metal ring will be a cathode (ignore the elements).

4) Now turn on the circuit and you will start to see the solution spilt with the the solution now being split some going to the anode and some going the cathode.

5) Then a thin layer should form on the electrode.

Hope this helps :)

5 0

3 years ago