1 mole of any gas under STP ----- 22.4 L
18.65 L*1 mol/22.4 L ≈ 0.8326 mol N2
Answer:
The answer is indeed true
Explanation:
Answer:

Explanation:
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In this case, according to this question, we will need to deal with this dilution problem, because it is asking for the volume of a 12.1-M stock solution of HCl. In such a way, we can use the following equation, under the assumption of no change in the number of moles in the solution:

Thus, we solve for the initial volume, V1, as shown below:

And plug in the initial concentration and final concentration and volume to obtain:

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Dirt and a chair are examples if solids. Some more examples are tables chips and blankets.