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3 years ago

How do you balance redox equations in acidic solutions?

Chemistry

1 answer:

Anuta_ua [19.1K]3 years ago

7 0

Answer:

First, balance the half-reactions

Second, equalize the electrons

Third,add two reaction equations to get final answer

Explanation:

For example

H₂C₂0₄ + MnO⁻₄ ---------->CO₂+Mn²⁺

(i) Balancing the half reactions

H₂C₂O₄-------->2CO₂+2H⁺+2e⁻

5e⁻ +8H⁺+MnO₄⁻----------->Mn²⁺+4H₂O

(ii)

Equalizing the electrons

5H₂C₂O₄--------->10CO₂+10H⁺+10e⁻ ---here there is a factor of 5

10e⁻+16H⁺+2MnO₄⁻--------->2Mn²⁺+8H₂O -----here there is a factor of 2

(iii)

Add the two where electrons and some Hydrogen ions will cancel out

5H₂C₂O₄+6H⁺+2MnO₄⁻---->10CO₂+2Mn²⁺+8H₂O

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Can soft drinks be part of a healthy diet?

mash [69]

Answer:

yes, but its better to drink water

Explanation:

6 0

2 years ago

The decomposition reaction of carbon disulfide to carbon monosulfide and sulfur is first order with k = 2.80 ✕ ✕ 10−7 sec-1 at 1

madam [21]

Answer: a) 1.97 grams of carbon disulfide will remain after 37.0 days.

b) 2.85 grams of carbon monosulfide will be formed after 37.0 days.

Explanation: The decomposition of carbon disulfide is given as:

$CS_2(g)\rightarrow CS(g)+S(g)$

at t=0 4.83g 0 0

at t=37 days 4.83 - x x x

here,

x = amount of $CS_2$ utilised in the reaction

This reaction follows first order kinetics so the rate law equation is:

$k=\frac{2.303}{t}log\frac{A_o}{A}$

where, k = rate constant

t = time

$A_o$ = Initial mass of reactant

A = Final mass of reactant

a) For this, the value of

$k=2.80\times10^{-7}sec^{-1}$

t = 370 days = 3196800 sec

$A_o$ = 4.83

A = 4.83-x

Putting values in the above equation, we get

$2.8\times 10^{-7}sec^{-1}=\frac{2.303}{3196800sec}log\left(\frac{4.83}{4.83-x}\right)$

x = 2.85g

Amount of $CS_2$ remained after 37 days = 4.83 - x

= 1.97g

b) Amount of carbon monosulfide formed will be equal to "x" only which we have calculated in the previous part.

Amount of carbon monosulfide formed = 2.85g

6 0

3 years ago

Who made the first periodic table

ale4655 [162]

The other dude is rude wrong

The correct answer is Dmitri Mendeleev

8 0

2 years ago

Name 5 things that the periodic table includes about 1 atom for each element:

olganol [36]

Answer:

They are listed below

Explanation:

The 5 things that the periodic table includes are;

1. Name of the element

2. The symbol of the element

3. Atomic number of the element

4. Relative atomic mass

5. Electron configuration

5 0

3 years ago

Phthalates used as plasticizers in rubber and plastic products are believed to act as hormone mimics in humans. The value of ΔHc

jeka94

Answer:

$T_f$ = 25.05°C

Explanation:

Given:

the value of ΔHcomb (heat of combustion) for dimethylphthalate (C10H10O4) is = 4685 kJ/mol.

mass = 0.905g of dimethylphthalate

molar mass = 194.18g dimethylphthalate

number of moles of dimethylphthalate = ???

$T_i$ = 21.5°C

$C_{calorimeter}$ = 6.15 kJ/°C

$T_f$ = ???

since we have our molar mass and mass of dimethylphthalate ;we can determine the number of moles as;

0.905g of dimethylphthalate × $\frac{1 mole (dimethylphthalate)}{194.184g(dimethylphthalate)}$

number of moles of dimethylphthalate = 0.000466 moles

Heat released = moles of dimethylphthalate × heat of combustion

= 0.000466 moles × 4685 kJ

= 21.84 kJ

∴ Heat absorbed by the calorimeter = $C_{calorimeter}$ $(T_f-T_i} )$

21.84 kJ =6.15 kJ/°C $* (T_f-21,5^0C)$

21.84 KJ = $(6.15 kJ/^0C * T_f) - (6.15 kJ/^0C*21.5^0C)$

21.84 KJ = $(6.15 kJ/^0C * T_f)$ - 132.225 kJ

21.84 KJ + 132.225 kJ = $(6.15 kJ/^0C * T_f)$

154.065 kJ = $(6.15 kJ/^0C * T_f)$

$T_f$ = $\frac{154.065kJ}{6.15kJ/^0C}$

$T_f$ =25.05°C

4 0

3 years ago