Answer:-1
Step-by-step explanation:-18-6n = 6 + 18n
-6n=6
divide
n=-1
Answer:
22 times
Step-by-step explanation:
Answer:
$ 4075.05
Step-by-step explanation:
Given :
R = Interest rate = 5.5%
T = Duration of Payment = 10 years
FV = Future Value
A = Amount
The amount of deposited in the account for 10 years from the date of initial deposit is $300
We are given that the Interest rate in the account is 5.5%
So by formula :
![FV = A(\frac{(1+r)^{t}-1}{r}).(1+r)](https://tex.z-dn.net/?f=FV%20%3D%20A%28%5Cfrac%7B%281%2Br%29%5E%7Bt%7D-1%7D%7Br%7D%29.%281%2Br%29)
![FV = 300(\frac{(1+.055)^{10}-1}{.055}).(1+ .055)](https://tex.z-dn.net/?f=FV%20%3D%20300%28%5Cfrac%7B%281%2B.055%29%5E%7B10%7D-1%7D%7B.055%7D%29.%281%2B%20.055%29)
![FV = 300(\frac{(1.055)^{10}-1}{.055}).(1.055)](https://tex.z-dn.net/?f=FV%20%3D%20300%28%5Cfrac%7B%281.055%29%5E%7B10%7D-1%7D%7B.055%7D%29.%281.055%29)
![FV = 300(\frac{1.708144458-1}{.055}).(1.055)](https://tex.z-dn.net/?f=FV%20%3D%20300%28%5Cfrac%7B1.708144458-1%7D%7B.055%7D%29.%281.055%29)
![FV = 300(\frac{0.708144458}{.055}).(1.055)](https://tex.z-dn.net/?f=FV%20%3D%20300%28%5Cfrac%7B0.708144458%7D%7B.055%7D%29.%281.055%29)
![FV = 300\times 12.875353782\times 1.055](https://tex.z-dn.net/?f=FV%20%3D%20300%5Ctimes%2012.875353782%5Ctimes%201.055)
![FV = 4075.05](https://tex.z-dn.net/?f=FV%20%3D%204075.05)
Thus , Total summation of money in the account after 10 years is given by the following equation =$ 4075.05
Total money in account after 10 years is $ 4075.05
Answer:
reflection
Step-by-step explanation:
the second picture is the same distance away form the y axis as the first picture
Answer:
second option, (u - 12 - 3b)/4
Step-by-step explanation:
isolate the "a" by bring each term to the other side, and finally div by 4
u = 12 + 4a + 3b
u - 12 = 4a + 3b
u - 12 - 3b = 4a
(u - 12 - 3b)/4 = a