Answer:
A) C is 2 units towards right
B) C is 9 units towards right and 3 units towards up
C) C is 4 units towards right and 1 unit towards down
Explanation:
Drawings are given in the attachment.
A)Since,
A is 4 units towards right,
B is 1 unit towards left,
Then,
C is 2 units towards right.
B) Since,
A is 4 units towards right and 2 units towards up,
B is 1 unit towards left,
Then,
C is 9 units towards right and 3 units towards up.
C) Since,
A is 4 units towards right and 2 units towards up,
B is 1 unit towards right, and 1 unit towards down
Then,
C is 4 units towards right and 1 unit towards down.
Answer:
D. TA < TB
Explanation:
From general gas equation, we know that:
PV = nRT
PV/R = nT
where,
P = pressure of gas
V = volume of gas
R = General gas constant
T = temperature of gas
n = no. of moles of gas
<u>FOR CYLINDER A</u>:
PV/R = (nA)(TA) _____ eqn (1)
<u>FOR CYLINDER B</u>:
PV/R = (nB)(TB) _____ eqn (2)
Because, Pressure, Volume are constant for both cylinders.
Comparing eqn (1) and (2)
(nA)(TA) = (nB)(TB)
It is given that the amount of gas in cylinder A is twice as much as the gas in cylinder B. This means the number moles in cylinder A are twice as much as no. of moles in cylinder B.
nA = 2(nB)
using this in eqn:
2(nB)(TA) = (nB)(TB)
TA = (1/2)(TB)
<u>TA = 0.5 TB</u>
Therefore it is clear that the correct option is:
<u>D. TA<TB</u>
<span>We know that an object in moving with acceleration follow the rule according that
the distance covered will be : d = Vi*t + 1/2*a*t^2
where d is distance, Vi is initial speed, and a is acceleration
Then after 1 km which is 1000 metres we have:
1000 = Vi *71.2 + 1/2*0.0499*(71.2)^2
Vi = (1000-1/2*0.0499*(71.2)^2)/71.2 = 1000/71.2 - 1/2*0.0499*71.2 = 12.27 m/s
Then the car was going at 12.27 m/s when started to accelerate.</span>
Answer: Two 10-cm-diameter charged rings face each other, 25.0cm apart. Both rings are charged to +20.0nC.
Explanation:
