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1 year ago

What are the three elements that magnets are made of?

Physics

1 answer:

tatuchka [14]1 year ago

4 0

Answer:

iron (Fe), cobalt

(Co), and nickel (Ni) .

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Light that has a wavelength of 554 nm is incident on a single slit that is 10 μm wide. Determine the angular location of the fir

VMariaS [17]

66.3 = 3% 9.528 correct 3.176 correct

7 0

3 years ago

A car is designed to get its energy from a rotating flywheel with a radius of 1.50 m and a mass of 430 kg. Before a trip, the fl

fiasKO [112]

Answer:

$KE = 7.17 *10^{7} \ J$

$t = 6411.09 \ s$

Explanation:

From the question we are told that

The radius of the flywheel is $r = 1.50 \ m$

The mass of the flywheel is $m = 430 \ kg$

The rotational speed of the flywheel is $w = 5,200 \ rev/min = 5200 * \frac{2 \pi }{60} =544.61 \ rad/sec$

The power supplied by the motor is $P = 15.0 hp = 15 * 746 = 11190 \ W$

Generally the moment of inertia of the flywheel is mathematically represented as

$I = \frac{1}{2} mr^2$

substituting values

$I = \frac{1}{2} ( 430)(1.50)^2$

$I = 483.75 \ kgm^2$

The kinetic energy that is been stored is

$KE = \frac{1}{2} * I * w^2$

substituting values

$KE = \frac{1}{2} * 483.75 * (544.61)^2$

$KE = 7.17 *10^{7} \ J$

Generally power is mathematically represented as

$P = \frac{KE}{t}$

=> $t = \frac{KE}{P}$

substituting the value

$t = \frac{7.17 *10^{7}}{11190}$

$t = 6411.09 \ s$

3 0

2 years ago

A basketball player of height 2.40 m is standing 2.60 m in front of a convex spherical mirror of radius of curvature 4.00 m. Det

IrinaVladis [17]

Answer:

The size of the image is 1.04 m.

Explanation:

Given that,

Height of object = 2.40 m

Distance of object = 2.60 m

Radius of curvature =4.00 m

Focal length $f=\dfrac{R}{2}=\dfrac{4.00}{2}=2.00$

We need to calculate the image distance

Using mirror formula

$\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}$

$\dfrac{1}{v}=\dfrac{1}{2.00}+\dfrac{1}{2.60}$

$\dfrac{1}{v}= \dfrac{23}{26}$

$v=1.13\ cm$

We need to calculate the height of the image

Using formula of magnification

$m=\dfrac{h'}{h}=-\dfrac{v}{u}$

Put the value into the formula

$\dfrac{h'}{2.40}=-\dfrac{1.13}{-2.60}$

$h'=\dfrac{1.13}{2.60}\times2.40$

$h'=1.04\ m$

Hence, The size of the image is 1.04 m

8 0

3 years ago

Leo places a plant in front of the center of curvature of a concave mirror. Which characteristics will the image of the plant ha

Ket [755]

1,3,5 that is the answer

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2 years ago

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Which conclusion is best supported by the data?

sattari [20]

Answer: b

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2 years ago

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