The final momentum of the ball is 3.8 kgm/s.
<h3>Change in momentum of the ball</h3>
The impulse received by the ball is equal to change in momentum of the ball.
J = ΔP
where;
- J is the impulse
- ΔP is change in momentum
ΔP = P₂ - P₁
P₂ = ΔP + P₁
<h3>Final momentum of the ball</h3>
The final momentum of the ball is calculated as follows;
P₂ = 8 + (- 0.1 x 42)
P₂ = 8 - 4.2
P₂ = 3.8 kgm/s
Learn more about change in momentum here: brainly.com/question/7538238
Answer:
D. from a separate pool than is the control group.
Explanation:
in the picture the person answers is backwards but...
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If we ignore air resistance, as we always do,
there is no horizontal acceleration.
Gravity acts only in the vertical direction, and
no other forces act on the ball after the punt.
Refer to the diagram shown below.
From the geometry, obtain
x = 2.5 - 0.55 = 1.95 m
cos θ = 1.95/2.5 = 0.78
θ = cos⁻¹ 0.78 = 38.74°
From the free body diagram, the tension in the chain is 450 N.
F is the centripetal force,
W is Dee's weight.
The components of the tension are
Horizontal component = 450 sin(38.74°) = 281.6 N, acting left.
Vertical component = 450 cos(38.74°) = 351.0 N, acting upward.
Answers:
Horizontal: 281.6, acting left.
Vertical: 351.0 N, acting upward.
Answer:
The value 
Explanation:
From the question we are told that
The acceleration due to gravity is a = 2g
The maximum height is h= 39 m
Generally from the kinematic equation

Here u is the velocity of the ball at maximum height before it start falling and the value is 0 m/s
So



