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3 years ago

Stephen Strasburg throws out the opening pitch at Nationals Park. The ball starts at rest, but

Physics

1 answer:

tankabanditka [31]3 years ago

4 0

Answer:

Force = 304.5 Newton

Explanation:

Given the following data;

Initial velocity, u = 0m/s (since it started from rest).

Final velocity, v = 42m/s

Time, t = 0.02 secs

Mass = 0.145 kg

To find the force;

First of all, we would have to determine the acceleration of the ball;

Acceleration = (v - u)/t

Acceleration = (42 - 0)/0.02

Acceleration = 42/0.02

Acceleration = 2100 m/s²

Now, we solve for the force;

Force = mass * acceleration

Force = 0.145 * 2100

Force = 304.5 Newton

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how long does it take an acorn to hit the ground after dropping from the branch of a tree 50.0m high? remember that g=9.8m/s^2

NeX [460]

D = V1( t ) + 1/2g( t )^2
50m = 0m/s( t ) + 1/2(9.8m/s^2)*( t )^2
V1*t cancels out
50m = (4.9m/s^2)*(t)^2
50m/(4.9m/s^2) = t^2
Metres unit cancels out so we are left with s^2
10.204s^2 = t^2
Square root both sides to cancel out square
t = 3.19 s

5 0

3 years ago

Read 2 more answers

A body of mass 40kg is accelerating at a

jok3333 [9.3K]

Momentum = (mass) x (speed)

Mass is constant, so the rate of change of momentum is
(mass) x (rate of change of speed) .

But (rate of change of speed ) is just acceleration.

So the rate of change of momentum is (mass) x (acceleration).

But (mass) x (acceleration) is Force.

So Force is the rate of change of momentum. Verrrrrrrry interesting !

In this problem, Force = (40 kg) x (9 m/s²) = 360 newtons.

One 'Newton' is one kilogram-meter per second² .
Unit of momentum is (kilogram)-(meter per second), so 'newton'
is also a unit of time rate of change of momentum.

Rate of change of momentum is 360 momentum units per second.

8 0

4 years ago

Read 2 more answers

The total circuit resistance is 6½ ohms. If a second 6½-ohm resistor is placed in parallel with the first, the total circuit res

mamaluj [8]

Answer:

Explanation:

It will increase cause the more branches you add the total current will increase

5 0

3 years ago

A projectile is thrown with an initial speed vo = 25.0 m/s at an initial angle with the horizontal ao = 45.0. a . Find the time

Natali [406]

Answer:

See the explanation below

Explanation:

To solve this problem we must decompose the initial speeds into x & y.

$v_{o}_{x}=25*cos(45)=17.67[m/s]\\v_{o}_{y}=25*sin(45)=17.67[m/s]\\$

The acceleration of gravity is equal to g = 9.81[m/s^2] downward.

The maximum height is when the velocity of the projectile is zero in the component y, that is, it will not be able to go higher, by means of the following kinematic equation we can find that time, for that specific condition.

$v_{y}=(v_{y})_{0}+a*t\\0 = 17.67 - 9.81*t\\17.67 = 9.81*t\\t=1.8 [s]$

Note: Acceleration is taken as negative as it is directed downwards.

The position in the x component can be found using the following kinematic equation

$x=(v_{x})_{o}*t\\x=17.67*1.8\\x=31.82[m]$

The position in the y component can be found using the following kinematic equation

$y =(v_{y})_{o}*t+\frac{1}{2} *g*t^{2} \\y=17.67*1.8-0.5*9.81*(1.8)^{2}\\ y=15.91[m]$

Since the motion on the X-axis is at constant speed, there is no acceleration, so the only acceleration that exists is due to gravity

In the attached image we can see, the projectile with the vectors of acceleration and velocity.

7 0

3 years ago

In the cabin of a plane cruising at 600km/hr, a pillow drops from the overhead bin onto your lap. Why does it not slam into the

algol [13]

Ground is 600 kilometers per hour
You is 0

3 0

3 years ago