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meriva
3 years ago
11

An ion's position vector is initially r = 8.0 i - 4.0 j + 3.0 k, and 8.0 s later it is r = 4.0 i + 8.0 j - 6.0 k, all in meters.

what was its vavg during the 8.0 s?
Physics
1 answer:
tangare [24]3 years ago
3 0

The average velocity = Displacement between two points/ Time taken for that displacement

In this case An ion's position vector is initially r = 8.0 i - 4.0 j + 3.0 k, and 8.0 s later it is r = 4.0 i + 8.0 j - 6.0 k

So, displacement = 4.0 i + 8.0 j - 6.0 k - (8.0 i - 4.0 j + 3.0 k)

                             = -4.0 i + 12.0 j - 9.0 k

So velocity, V = (-4.0 i + 12.0 j - 9.0 k)/8

                      = -0.5 i + 1.5 j - 1.125 k

So average velocity during 8 seconds = -0.5 i + 1.5 j - 1.125 k

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A same-size iron ball and wooden ball are dropped simultaneously from a tower and reach the ground at the same time. The iron ba
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Answer:

momentum of iron ball is greater than wooden ball

Explanation:

when metal ball (iron ball) and wooden drop are drop from same elevation and reaching the ground after same time. at this position the iron ball has greater momentum than wooden ball

we know that momentum is defined as

P=Mv

and we know also that mass of iron ball is greater than mass of wooden ball and they reached on ground at same time  and same distance it mean also velocity will be same for both ball. therefore from above relation we have

Miron*V > Mwood*V i.e.

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4 years ago
Consider water flowing through a cylindrical pipe with a variable cross-section. The velocity is v at a point where the pipe dia
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one ninth

Explanation:

d = 1 cm , v = v

D = 3d, V = ?

By the equation of continuity,

A V = a v

3.14 x D^2 / 4 x V = 3.14 x d^2 / 4 x v

9d^2 x V = d^2 x v

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3 years ago
A uniform solid disk and a uniform ring are place side by side at the top of a rough incline of height h.
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Explanation:

velocity of disc =\sqrt((gh)/0.75)

lets call (h) 1 m to make it simple.

= 3.614 m/s

\sqrt((4/3) x 1 x 9.8) = 3.614 m/s pointing towards this:

4×V_d=\sqrt(4/3hg)

V_h=\sqrt(hg)

velocity of hoop=\sqrt(gh)

lets call (h) 1m to make it simple again.

\sqrt(9.8 x 1) = 3.13 m/s

\sqrt(gh) = sqrt(hg)so [tex]4×V_d= \sqrt(4/3hg)V_h=\sqrt(hg)

The disc is the fastest.

While i'm on this subject i'll show you this:

Solid ball =0.7v^2= gh

solid disc = 0.75v^2 = gh

hoop =v^2=gh

The above is simplified from linear KE + rotational KE, the radius or mass makes no difference to the above formula.

The solid ball will be the faster of the 3, like above i'll show you.

solid ball: velocity =\sqrt((gh)/0.7)

let (h) be 1m again to compare.

\sqrt((9.8 x 1)/0.7) = 3.741 m/s

solid disk speed =\sqrt((gh)/0.75)

uniform hoop speed =\sqrt(gh)

solid sphere speed =\sqrt((gh)/0.7)

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What are the things ships tie up to at dock?
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