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2 years ago

In order to create an electromagnet, you would ?

2 answers:

4 0

In order to create an electromagnet, you would wrap an insulated wire around a metal with ferromagnetic properties and apply electric current. Magnetic fields are made when entirely the electrons are turning in the same direction either as a natural phenomenon, in an artificially created magnet or when they are persuaded to do so by an electromagnetic field.

alex41 [277]2 years ago

4 0

Electromagnet is an temporary magnet produced when electric current is passed through specific materials.

The process of production of electromagnet is explained as follows :

From Oersted's law, we know that a current carrying conductor produces a magnetic field around it.

The same principle is applied in the production of electromagnet.

A ferromagnetic material is wound by insulated copper wires. The current is allowed to pass through wounded ferromagnetic material which in turn, produces magnetic field around it, and acts just like a strong electromagnet.

The magnetism is retained as long as there is current flow in the wire.

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Mixing of sand in water is an irreversible change true aur false

USPshnik [31]

Answer:

Explanation:

<h3>hope it helps you ❤️</h3><h3>happy to help</h3>

3 0

2 years ago

Assume that you have a rectangular tank with its top at ground level. The length and width of the top are 14 feet and 7 feet, re

ch4aika [34]

To solve this problem we will use the work theorem, for which we have that the Force applied on the object multiplied by the distance traveled by it, is equivalent to the total work. From the measurements obtained we have that the width and the top are 14ft and 7ft respectively. In turn, the bottom of the tank is 15ft. Although the weight of the liquid is not given we will assume this value of $62 lb / ft ^ 3$ (Whose variable will remain modifiable until the end of the equations subsequently presented to facilitate the change of this, in case be different). Now the general expression for the integral of work would be given as

$W = \gamma A * \int_0^15 dy$

Basically under this expression we are making it difficult for the weight of the liquid multiplied by the area (Top and widht) under the integral of the liquid path to be equivalent to the total work done, then replacing

$W = (62)(14*7)\int^{15}_0 (15-y)dy$

$W = (14*7*62)\big [15y-\frac{y^2}{2}\big ]^{15}_0$

$W = (14*7*62)[15(15)-\frac{(15)^2}{2}]$

$W = 683550ft-lbs$

Therefore the total work in the system is $683550ft-lbs$

6 0

3 years ago

Suppose the moon rotated on its axis just as quickly as Earth. Would we still always see the same side of the moon from Earth?

jasenka [17]

Answer:

No, The Moon, on the other hand, rotates once around its every 28 days, and once around the Earth in that same 28 days. The result of this combination is that the same side of the Moon is always facing the Earth.

3 0

2 years ago

A box rests on the (horizontal) back of a truck. The coefficient of static friction between the box and the surface on which it

vredina [299]

Answer:

The distance is 11 m.

Explanation:

Given that,

Friction coefficient = 0.24

Time = 3.0 s

Initial velocity = 0

We need to calculate the acceleration