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belka [17]
3 years ago
6

In order to create an electromagnet, you would ?

Physics
2 answers:
Yakvenalex [24]3 years ago
4 0
In order to create an electromagnet, you would wrap an insulated wire around a metal with ferromagnetic properties and apply electric current. Magnetic fields are made when entirely the electrons are turning in the same direction either as a natural phenomenon, in an artificially created magnet or when they are persuaded to do so by an electromagnetic field. 
alex41 [277]3 years ago
4 0

Electromagnet is an temporary magnet produced when electric current is passed through specific materials.

The process of production of electromagnet is explained as follows :

From Oersted's law, we know that a current carrying conductor produces a magnetic field around it.

The same principle is applied in the production of electromagnet.

A ferromagnetic material is wound by insulated copper wires. The current is allowed to pass through wounded ferromagnetic material which in turn, produces magnetic field around it, and acts just like a strong electromagnet.

The magnetism is retained as long as there is current flow in the wire.

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How does inertia affect the motion of an object?
Furkat [3]

<u>Inertia affects the motion of an object as follows:</u>

When an object is in motion, it will continue to be in the same state unless otherwise some outside force is being applied to it. Thus, inertia affects the motion of an object. It restricts some other force being acted upon the object.

But mass of an object is directly proportional to inertia. So when the inertia is more on an object, it means that the object has more mass. For example, if there are two similar bricks, one that is made up of mortar and the other one is made of Styrofoam.

To identify which brick is made of Styrofoam without lifting the bricks, push both the bricks with equal force, the one that has less resistance tends to move faster. This means that it has less inertia and hence less mass.

4 0
3 years ago
Suppose we hang a heavy ball with a mass 13 kg (so the weight is ) from a steel wire 3.9 m long that is 3.1 mm in diameter (radi
Katena32 [7]

Answer:

1.635×10^-3m

Explanation:

Young modulus is the ratio of the tensile stress of a material to its tensile strain.

Young modulus = Tensile stress/tensile strain

Tensile stress = Force/Area

Given force = 130N

Area = Πr² = Π×(1.55×10^-3)²

Area = 4.87×10^-6m²

Tensile stress = 130/4.87×10^-6 = 8.39×10^7N/m²

Tensile strain = extension/original length

Tensile strain = e/3.9

Substituting in the young modulus formula given young modulus to be 2×10¹¹N/m²

2×10¹¹N/m² = 8.39×10^7/{e/3.9)}

2×10¹¹ = (8.39×10^7×3.9)/e

2×10¹¹e = 3.27×10^8

e = 3.27×10^8/2×10¹¹

e = 1.635×10^-3m

The stretch of the steel wire will be

1.635×10^-3m

7 0
3 years ago
Instructions:Select the correct answer from the drop-down menu. The Longmenshan Fault is in China. This fault was created when t
lina2011 [118]
I say Reverse Fault, Hope this helps :)
3 0
3 years ago
A fuel pump sends gasoline from a car's fuel tank to the engine at a rate of 5.64 10-2 kg/s. the density of the gasoline is 735
Irina18 [472]
Given:
Gasoline pumping rate, R = 5.64 x 10⁻² kg/s
Density of gasoline, D = 735 kg/m³
Radius of fuel line, r = 3.43 x 10⁻³ m

Calculate the cross sectional area of the fuel line.
A = πr² = π(3.43 x 10⁻³ m)² = 3.6961 x 10⁻⁵ m²

Let v =  speed of pumping the gasoline, m/s
Then the mass flow rate is 
M = AvD = (3.6961 x 10⁻⁵ m²)*(v m/s)*(735 kg/m³) = 0.027166v kg/s

The gasoline pumping rate is given as 5.64 x 10⁻² kg/s, therefore
0.027166v = 0.0564
v = 2.076 m/s

Answer:  2.076 m/s
The gasoline moves through the fuel line at 2.076 m/s.
7 0
3 years ago
Read 2 more answers
QUESTION:
vampirchik [111]

Answer:

I don't know why you are asking me?

5 0
2 years ago
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