Ask question

Ask question

All categories

3 years ago

11

The resolving power of electron microscopes is much better than the resolving power of light microscopes because the wavelength

of electron beams is ________ than the wavelength of visible light.

1 answer:

Misha Larkins [42]3 years ago

6 0

Answer:

because the wavelength of electron beams is much shorter than the wavelength of visible light

You might be interested in

A ball is dropped from the top of a building.After 2 seconds, it’s velocity is measured to be 19.6 m/s. Calculate the accelerati

zlopas [31]

Answer:

acceleration, a = 9.8 m/s²

Explanation:

'A ball is dropped from the top of a building' indicates that the initial velocity of the ball is zero.

u = 0 m/s

After 2 seconds, velocity of the ball is 19.6 m/s.

t = 2s, v = 19.6 m/s

Using

v = u + at

19.6 = 0 + 2a

a = 9.8 m/s²

6 0

3 years ago

Read 2 more answers

Two capacitors, a 15 micro F and a 25 micro F, are connected in parallel to a 60 Hz source. The total capacitive reactance is :_

Stells [14]

Answer:

<em> 3980.89 ohms</em>

Explanation:

The capacitive reactance is expressed as;

$X_c = \frac{1}{2 \pi fC}$

f is the frequency

C is the capacitance of the capacitor

Given

f = 60H

C = C1+C2 (parallel connection)

C = 15μF + 25μF

C = 40μF

C = $40 * 10^{-6}F$

Substitute into the formula:

$X_c = \frac{1}{2(3.14)*60*40*10^{-6}}\\X_c = \frac{1}{0.0002512}\\X_c = 3,980.89$

<em>Hence the total capacitive reactance is 3980.89 ohms</em>

5 0

3 years ago

What is the anomalous expansivity of water

salantis [7]

Answer:

The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from 4°C to 0°C, and it becomes less dense. The density becomes less and less as it freezes because molecules of water normally form open crystal structures when in solid form.

7 0

3 years ago

To raise an arm upward, the muscle on one side of it contracts. What happens to the muscle on the opposite side of the arm?

enyata [817]

Answer:

It relaxes

Explanation:

I took the test I hope it helps

5 0

3 years ago

Read 2 more answers

Use the dot product to find the magnitude of u if u = 6i - 3j

LuckyWell [14K]

Vector u :
u = 6 i - 3 j
The magnitude of vector u :
| u | = $\sqrt{6 ^{2}+(-3) ^{2} } = \sqrt{36+9}= \\ \sqrt{45}= \sqrt{9*5}=3 \sqrt{5}$
Answer:
The magnitude of vector u is 3√5.

3 0

3 years ago