Following the Hardy-Weinberg equilibrium theory, the frequency of the heter0zyg0us genotype is 2pq. In the exposed example, 2pq = 0.48.
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Hardy-Winberg equilibrium</h3>
The Hardy-Weinberg equilibrium theory states that the allelic frequencies in a locus are represented as p and q.
Assuming a diallelic gene,
→ The allelic frequencies are
- p is the frequency of the dominant allele,
- q is the frequency of the recessive allele.
→ The genotypic frequencies after one generation are
- p² (H0m0zyg0us dominant genotypic frequency),
- 2pq (Heter0zyg0us genotypic frequency),
- q² (H0m0zyg0us recessive genotypic frequency).
If a population is in H-W equilibrium, it gets the same allelic and genotypic frequencies generation after generation.
The addition of the allelic frequencies equals 1 ⇒ p + q = 1.
The sum of genotypic frequencies equals 1 ⇒ p² + 2pq + q² = 1
If the allele A has a frequency of 0.6, and the allele B has a frequency of 0.4, then the frequency of the heter0zyg0us genotype is
2pq = 2 x 0.6 x 0.4 =<u> 0.48</u>
You can learn more about the Hardy-Weinberg equilibrium at
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The answer to this question is the term rhizome. A rhizome is a stem of a plant that is growing underground and is growing horizontally. It is also known as rootstocks. The rhizome's function in the plant is that it is used to store starches and protein that enables the plant to grow underground.
Answer:
:the natural process of bone formation.
