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Alinara [238K]
3 years ago
9

The graph of a quadratic function F has zeros of -8 and four and a maximum at -2, 18 what is the value of “a” in the function eq

uation?
Mathematics
1 answer:
scoray [572]3 years ago
8 0
Hi I am the answer to dat
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What is the approximate value of x in the diagram below
irga5000 [103]

We use Tan in this case:

Tan=(opposite/adjacent)

Tan(36)=23/x

x=23/Tan(36)

x=31.64 length

Hope it helps!

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2 years ago
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Factor the four-term polynomial.
Morgarella [4.7K]
<span>(n + 3) • (m - 5) is the correct answer and I hope this helped you out.  </span>
8 0
3 years ago
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Adam is subtracting 708 – 10 mentally. He thinks
solong [7]
Adam is correct because when the hundreds and tens digit changes in 708, that means that the 7 and 0 will change into 6 and 9
8 0
3 years ago
Express the fractions 1/2, 3/16, and 7/8 with an LCD
12345 [234]
You first need to find the LCD (lowest common denominator). You will need to find the smallest number that is a multiple of all numbers that is the denominator (2, 16, 8). Or, to say it another way, all the numbers in the denominator need to be a factor of this number. 

You can find this by first checking if the largest number that is the denominator-- in this case 16-- is already the LCD, which means 16 is divisible by all the other numbers. 

If this does not work, then multiply all the numbers together to get the LCD-- since you multiplied them together, you know that they will all be factors of the product. 

However, you will be able to see that 16 is indeed the lowest common denominator: 

2 × 8=16 

8 × 2=16 

16 × 1=16 

So, after you find the LCD, multiply both the numerator and the denominator by the number that you would need to multiply the denominator to get the LCD (the whole point is that you want to get the denominator to be the LCD, but to do that you need to multiply both the top and bottom by the same number to keep the fraction the same). 

(1/2) x (8/8)= 8/16 

(3/16) x (1/1)= 3/16 

(7/8) x (2/2)= 14/16

6 0
3 years ago
At 88°F, a certain insect chirps at a rate of 64 times per minute, and at 97°F, they chirp 118 times per minute. Write an equati
Allushta [10]

Let " x "  denotes the temperature in degree Fahrenheit .

Let  " y " denotes the chirp rate per minute .

We have given that at 88 degree Fahrenheit , chirp rate is 64 times per minute and at 97 degree Fahrenheit , it is 118 times per minute .

We write this information in coordinate form ( x,y) .

We have ( x₁ ,y₁)  = ( 88 , 64 )  and  ( x₂ , y₂) = ( 97,118) .

                         y₂   - y ₁                     118  -   64                  54

Slope , m  =  ----------------------  =    ---------------------  =     -----------

                          x₂  - x₁                        97   -  88                   9

           Slope , m =  6 .


Equation of line in slope intercept form is

y = m x + b  where  ' m' is slope and ' b ' is intercept .

Plug value of m  , we get

y = 6 x + b .

To find value of b , we put ( 88 , 64 ) in place of x and y .

Put x = 88 and y = 64 , we get

64 = 6 * 88 + b

64  = 528 + b

64 - 528 =  b

- 464 = b

Thus we get b = - 464 .

So the equation become

y = 6 x - 464 .

Equation in slope intercept form representing the situation is

y = 6 x - 464 .

6 0
3 years ago
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