Question

How many moles of butane gas, C4H10, react to produce 2.50 moles of H2O? How many moles of oxygen gas reacts? Given the balanced equation is, 2C4H10+13O2 = 8CO2+10H2O

Answer 1

The moles  of  butane gas  and  oxygen gas reacted  if  2.50  moles  of H2O is produced  is  calculated  as below

the  equation  for  reaction
2C4H10  +13 O2 = 8CO2 +10 H2O

the moles  of  butane (C4H10) reacted calculation

by  use  of mole ratio between  C4H10: H2O  which  is  2  : 10 the  moles of  C4H10=     2.50  x2/10 = 0.5 moles  of  C4H10  reacted

The  moles of  O2  reacted calculation

by  use of mole  ratio  between   O2 : H2O  which  is  13:10 the moles of O2

=   2.50  x 13/10=  3.25  moles of O2  reacted