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Levart [38]
3 years ago
14

PLEASE HELP!!! Dhdjdhdjwjwnwisidjdnswnsjsjsksk

Chemistry
1 answer:
Aneli [31]3 years ago
5 0

Answer:

i think i can answer that because the question is not defined so its hard for me to answer

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What is the name of the binary compound Mg3 (PO3)2? A. magnesium phosphate B. magnesium phosphide C. Tri magnesium diphosphite D
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B) Magnesium Phosphide
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Write the net ionic equation for the reaction that takes places between aqueous copper and nitrate.
PIT_PIT [208]

Answer:

Cu+HNO3

Explanation:

7 0
3 years ago
The substance whose lewis structure shows three covalent bonds is
Gnoma [55]

The substance whose Lewis structure shows three covalent bonds is Nitrogen gas molecule.

<h3>What is Lewis structure?</h3>

Lewis structure is a dot structure which gives idea about the number of valence electrons that are involved in the bonding within the molecule.

Lewis dot structure of nitrogen gas will be expressed as in the attached image, where between two nitrogen atoms triple bond is present. That triple bond is formed by the sharing of electrons and known as covalent bonds.

Hence in nitrogen gas molecule three covalent bonds is present.

To know more about Lewis structure, visit the below link:
brainly.com/question/21026664

#SPJ4

4 0
2 years ago
Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 30.0 °C for the following reacti
gayaneshka [121]

Answer : The value of K for this reaction is, 2.6\times 10^{15}

Explanation :

The given chemical reaction is:

CH_3OH(g)+CO(g)\rightarrow HCH_3CO_2(g)

Now we have to calculate value of (\Delta G^o).

\Delta G^o=G_f_{product}-G_f_{reactant}

\Delta G^o=[n_{HCH_3CO_2(g)}\times \Delta G^0_{(HCH_3CO_2(g))}]-[n_{CH_3OH(g)}\times \Delta G^0_{(CH_3OH(g))}+n_{CO(g)}\times \Delta G^0_{(CO(g))}]

where,

\Delta G^o = Gibbs free energy of reaction = ?

n = number of moles

\Delta G^0_{(HCH_3CO_2(g))} = -389.8 kJ/mol

\Delta G^0_{(CH_3OH(g))} = -161.96 kJ/mol

\Delta G^0_{(CO(g))} = -137.2 kJ/mol

Now put all the given values in this expression, we get:

\Delta G^o=[1mole\times (-389.8kJ/mol)]-[1mole\times (-163.2kJ/mol)+1mole\times (-137.2kJ/mol)]

\Delta G^o=-89.4kJ/mol

The relation between the equilibrium constant and standard Gibbs, free energy is:

\Delta G^o=-RT\times \ln K

where,

\Delta G^o = standard Gibbs, free energy  = -89.4 kJ/mol = -89400 J/mol

R = gas constant  = 8.314 J/L.atm

T = temperature  = 30.0^oC=273+30.0=303K

K = equilibrium constant = ?

Now put all the given values in this expression, we get:

-89400J/mol=-(8.314J/L.atm)\times (303K)\times \ln K

K=2.6\times 10^{15}

Thus, the value of K for this reaction is, 2.6\times 10^{15}

4 0
4 years ago
When performing labratory experiments, which of the following items is ALWAYS necessary to use?
densk [106]
All of the the answers are are correct but a fume hood is more for if you are dealing with chemicals that can produce fumes the are deadly to people
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4 years ago
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