There are three answers, the impulse is equal to the change in momentum of the system. The dimensions of these quantities are the same, namely mass times velocity. You can think of impulse as kind of the "net effect" that a force has in changing the state of motion of a system.
A. Starts slowly and then accelerates.
Answer:
745.4K ~ 472.3 C
Explanation:
This is an Ideal Gas Law problem where we have to manipulate the equation a bit. Let's start with the basic:
PV = nRT will be used for both the initial and final, so we will rearrange this problem to state:
(V(initial))/(T(Initial)) = nR/P
Since we know that the pressure, number of moles of He, and ideal gas constant (R) remain the same from start to finish so we can write the problem as such:
(V(initial))/(T(Initial)) = nR/P = (V(final))/(T(final))
or
(V(initial))/(T(Initial)) = (V(final))/(T(final))
Now lets define some of these values:
T(initial) = 25degree (assuming degrees Celsius) ~ 298.15K
V(initial) = 2.0L
V(final) = 5.0L
T(final) = ?
Since we are solving for T(final) let's rearrange the problem once more to be solving for T(final):
T(final) = (V(final)T(Initial))/V(initial)
Now plug in your values:
T(final) = (5.0L*298.15K)/(2.0L) ~ 745.4K ~ 472.3degrees Celsius
Answer:
a ) 4.5 N.s
b) V =5 m/s
Explanation:
given,
mass of rifle(M) = 0.9 kg
mass of bullet(m) = 6 g = 0.006 kg
velocity of the bullet(v) = 750 m/s
a) momentum of bullet = m × v
= 750 × 0.006
= 4.5 N.s
b) recoil velocity
m × u + M × U = m × v + M × V
0 + 0 = 0.006 × 750 - 0.9 × V
V =
V =5 m/s