A rifle with a mass of 0.9 kg fires a bullet with a mass of 6.0 g (0.006 kg). The bullet moves with a muzzle velocity of 750 m/s
1 answer:
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Answer:
F = 0.1575 N
Explanation:
When the third sphere touches the first sphere, the charge is distributed between both spheres, then now the first sphere has only half of his original charge.
In this moment then
Sphere one has a charge = Q/2
Sphere three has a charge = Q/2
Now when the third sphere touches the second sphere again the charge is distributed in a manner that both sphere has the same charge.
How the total charge is Q = Q/2 + Q = 3/2Q, when the spheres are separated each one has 3/4Q
Sphere two has a charge = 3/4Q
Sphere three has a charge = 3/4Q
The electrostatic force that acts on sphere 2 due to sphere 1 is:
F =
F=
how = 0.42
Then
F =
F = 0.1575 N
The magnitude of the displacement current between the plates is
Given,
A=4.3*
=
*A*
=
= -=
An electrical charge carrier flow known as current often involves electrons or atoms lacking in electrons. The capital letter I is frequently used as a symbol for current. Amperes are the common unit and are denoted by the letter A. A coulomb of electrical charge moves past a certain place in one second as one ampere of current does. Franklin current or conventional current are terms used by physicists to describe how current flows from relatively positive to comparatively negative sites. Negatively charged electrons are the most prevalent charge carriers. They move in a somewhat good direction from relatively negative points.
With e in volts per meter and t in seconds. at t = 0, the field is upward. the plate area is 4. 3 × 10-2 m2. for t > 0, what is the magnitude of the displacement current between the plates?
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