Answer:
V = 19m/s
Explanation:
Given the following data;
Initial velocity, U = 4m/s
Acceleration, a = 0.5m/s²
Time, t = 30 seconds
To find the final velocity, we would use the first equation of motion;
V = U + at
Where;
V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.
V = 4 + 0.5*30
V = 4 + 15
V = 19m/s
Therefore, his final velocity is 19 meters per seconds.
Answer:
Δt = 5.85 s
Explanation:
For this exercise let's use Faraday's Law
emf =
- d fi / dt
= B. A
\phi = B A cos θ
The bold are vectors. It indicates that the area of the body is A = 0.046 m², the magnetic field B = 1.4 T, also iindicate that the normal to the area is parallel to the field, therefore the angle θ = 0 and cos 0 =1.
suppose a linear change of the magnetic field
emf = - A 
Dt = - A 
the final field before a fault is zero
let's calculate
Δt = - 0.046 (0- 1.4) / 0.011
Δt = 5.85 s
The number of ocean waves that pass a buoy in one second is the frequency of the <span>wave. The crest of a transverse wave is its highest point. </span>