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enyata [817]
3 years ago
8

Write the equation of the line perpendicular to 2x-5y=-12 that passes through the point (10,-1) in slope-intercept form.

Mathematics
1 answer:
m_a_m_a [10]3 years ago
4 0

Answer:

y=-\frac{5}{2}x-24

Step-by-step explanation:

2x-5y=-12\\5y=2x+12\\y=\frac{2}{5}x+\frac{12}{5}\\

if two lines perpendicular,

m_{1} .m_{2}=-1\\ \frac{2}{5} .m_{2}=-1\\m_{2}=-\frac{5}{2}

the line perpendicular to this line is

y=-\frac{5}{2}x+k ; k ∈ R

the line passes through the point (10,-1)

so,

-1=-\frac{5}{2} (10)+k\\-1=-25+k\\k=-24

∴the equation of the line perpendicular to 2x-5y=-12 that passes through the point (10,-1) is

y=-\frac{5}{2}x-24

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