Question

Identify the discontinuity and zero of the function f(x)= 4x/x^2-16

Answer 1

Answer:

Step-by-step explanation:

ANSWER

Point if discontinuity:  

{x}=  \pm3

Zero of the function is  

x = 0

EXPLANATION

The given rational function is:

f(x) =  \frac{3x}{ {x}^{2}  - 9}  

This function is not continous when  

{x}^{2}  - 9 = 0

{x}=  \pm \sqrt{9}  

{x}=  \pm3

The function is zero when,

3x = 0

x = 0

Answer 2

Answer:

x = 0 is the zero of this function and at x = ±4 function is discontinuous.

Step-by-step explanation:

The given function is $f(x) = \frac{4x}{x^{2}-16}$

For this function we have to find the discontinuity and zeros of this function.

For zeros of the function $0 = \frac{4x}{x^{2}-16}$

so zero of the function is x = 0

For x² - 16 = 0 this function not defined therefore, x = ± 4 function will be discontinuous.

Finally, x = 0 is the zero of this function and at x = ±4 function is discontinuous.