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3 years ago

Identify the discontinuity and zero of the function f(x)= 4x/x^2-16

Mathematics

2 answers:

Oduvanchick [21]3 years ago

6 0

Answer:

Step-by-step explanation:

ANSWER

Point if discontinuity:

{x}= \pm3

Zero of the function is

x = 0

EXPLANATION

The given rational function is:

f(x) = \frac{3x}{ {x}^{2} - 9}

This function is not continous when

{x}^{2} - 9 = 0

{x}= \pm \sqrt{9}

{x}= \pm3

The function is zero when,

3x = 0

x = 0

neonofarm [45]3 years ago

4 0

Answer:

x = 0 is the zero of this function and at x = ±4 function is discontinuous.

Step-by-step explanation:

The given function is $f(x) = \frac{4x}{x^{2}-16}$

For this function we have to find the discontinuity and zeros of this function.

For zeros of the function $0 = \frac{4x}{x^{2}-16}$

so zero of the function is x = 0

For x² - 16 = 0 this function not defined therefore, x = ± 4 function will be discontinuous.

Finally, x = 0 is the zero of this function and at x = ±4 function is discontinuous.

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Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand

Misha Larkins [42]

<u>Answer:</u>

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2

And a standard deviation of 3.6.

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

$\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2$

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

$\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1$

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0

3 years ago

A parabolic mirror to be used in a

jok3333 [9.3K]

I’m sorry if I’m wrong I’d stay safe and let someone anwser tell u but I think 20

8 0

3 years ago

I need help i will give brainiest question in screenshot

Thepotemich [5.8K]

Answer:

ok so first you have to know what a reflectiin along 180 is

) A point P(x,y)P(x,y) is rotated 180180 degrees about the origin, then reflected over the y-axis. What is the resulting image of PP?

My conjecture: (−x,y)(−x,y) but I don't quite agree with it graphically. I'm having trouble with what exactly a 180 degree rotation about the origin simply is.

2) A point P(x,y)P(x,y) is reflected over the y-axis and then rotated 180 degrees about the origin. What is the resulting image?

Is this the same thing as 1?

3) A point A(x,y)A(x,y) is reflected over the line y=xy=x and then reflected over the y-axis. What is the resulting image of A?

My conjecture: (−y,x)(−y,x)

4) A point A(x,y)A(x,y) is reflected over the lines y=−xy=−x and then reflected over the y-axis. What is the resulting image of A?

My conjecture: (y,−x)

ok you need to know what thouse meen

Step-by-step explanation:

)If P(x1,y1)P(x1,y1) is rotated angle ϕϕ about O(a,b)O(a,b) to P′(x′,y′)P′(x′,y′)

we have |OP|=|OP′||OP|=|OP′| and |arctanmOP−arctanmOP'|=ϕ|arctan⁡mOP−arctan⁡mOP'|=ϕ

By atan(z)(z) I imply atan2

(2)If P(x1,y1)P(x1,y1) is reflected over L:ax+by+c=0L:ax+by+c=0 and the resulting image of PP is Q(x2,y2) (1)Q(x2,y2) (1)

We have R

so i hope thiz helprs you

3 0

3 years ago

There are 10 less trumpet players than saxophone players. The number of saxophone playere is 3 times thr number of trumpet playe

just olya [345]

I'm guessing it 30 it says 3 times the nber of trumpet players

7 0

3 years ago

A ball is thrown at an initial height of 7 feet with an initial upward velocity at 27 ft/s. The balls height h (in feet) after t

lianna [129]

Answer:

The height of ball is 17 ft at t=0.55 and t=1.14.

Step-by-step explanation:

The general projectile motion is defined as

$y=-16t^2+vt+y_0$

Where, v is initial velocity and y₀ is initial height.

It is given that the initial height is 7 and the initial upward velocity is 27.

Substitute v=27 and y₀=7 in the above equation to find the model for height of the ball.

$h(t)=-16t^2+27t+7$

The height of ball is 17 ft. Put h(t)=17.

$17=-16t^2+27t+7$

$0=-16t^2+27t-10$

On solving this equation using graphing calculator we get

$t=0.549,1.139$

$t\approx 0.55,1.14$

Therefore the height of ball is 17 ft at t=0.55 and t=1.14.

3 0

3 years ago