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velikii [3]
3 years ago
5

Which of these components is not necessary for current to flow in a series or parallel circuit?

Physics
2 answers:
RUDIKE [14]3 years ago
5 0
Only wire is necessary.

A switch is only needed if you want to be able to turn the current on and off easily.

A resistor is only needed if you want to generate some heat or limit the current.
Zielflug [23.3K]3 years ago
4 0
All the components (D) ie, wire, switch and resistor are needed for current to flow in a series or parallel circuit.  
In a simple series circuit, all the components are connected end-to-end to form a single path for the electrons or electric current to flow through the circuit. A simple parallel circuit is where all the components in the circuit are connected between the same two sets of common points, creating a more than one path for the electrons or electric current to flow around the circuit. 

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4 years ago
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When ultraviolet light with a wavelength of 400.0 nm falls on a certain metal surface, the maximum kinetic energy of the emitted
Andru [333]

Answer:

Explanation:

energy of photon having wavelength of 400 nm = 1237.5/400 eV

= 3.1 eV.

Maximum kinetic energy of photoelectrons = 1.1 eV .

Threshold energy Ф = 3.1 - 1.1 = 2 eV .

energy of photons having wavelength of 310 nm = 1237.5 / 310 eV = 4 eV .

Maximum kinetic energy of photoelectrons = energy of photons - Threshold energy

= 4 - 2 = 2 eV .

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8 0
3 years ago
A physical science test book has a mass of 2.2 kg. what is the weight on the Earth
Step2247 [10]

Weight = (mass) x (acceleration of gravity).

On Earth, acceleration of gravity = 9.8 m/s² (rounded)

On Earth, 2.2kg of mass weighs (2.2kg) x (9.8 m/s²) =

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6 0
4 years ago
The atomic radii of Li+and O2−ions are 0.068 and 0.140 nm, respectively.(a) Calculate the force of attraction between these two
sasho [114]

Answer:

Part a)

F_{attraction} = 1.06 \times 10^{-8} N

Part b)

F_{repulsion} = 1.06 \times 10^{-8} N

Explanation:

Part a)

Equilibrium distance is the distance between two centers when two ions just touch each other

So here we will have

r = 0.068 nm + 0.140 nm

r = 0.208 nm

Now Force of attraction between two ions is given by Coulomb's law

F = \frac{kq_1q_2}{r^2}

F = \frac{(9\times 10^9)(1.6 \times 10^{-19})(2\times 1.6 \times 10^{-19})}{(0.208\times 10^{-9})^2}

F_{attraction} = 1.06 \times 10^{-8} N

Part b)

At equilibrium separation net force between two ions must be zero

F_{attraction} = F_{repulsion}

so the attraction force and repulsion force must be of equal magnitude

so we have

F_{repulsion} = 1.06 \times 10^{-8} N

6 0
3 years ago
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