Applying the translation rule:
G(0, 4) → (0-5, 4+2) → G'(-5, 6)
Answer:
The expanded form of the expression
is 
Step-by-step explanation:
We need to write expanded form of the expression 
For expansion we will use distributive property of multiplication over addition

Applying above rule:

So, the expanded form of the expression
is 
Are there any options for us to choose or is there none because I could do it backward
Answer:
-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2
Step-by-step explanation:
-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2-11x-7=-3x^2