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wel
3 years ago
10

Five percent of what number is 1.25

Mathematics
1 answer:
shutvik [7]3 years ago
8 0
25
25 x 5%= 1.25

Idk how much better to explain it
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15x-60
this is the answer
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3 years ago
(x – 4)(x+6)<br> Need help simplify
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The answer would be 2x^2+2x-24

using foil, you would multiply together x & x, x & 6, -4 & x, and -4 & 6, then add them together.
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Area of Composed Figures - Quiz-Level G
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The number of square feet of the carpet is the area of the carpet

The number of square feet of outdoor carpet is 32 feet

<h3>How to determine the number of square feet</h3>

To do this, we simply divide the carpet to regular shapes.

The outdoor carpet can be divided to the following shapes from top to bottom

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So, the area of the outdoor carpet is:

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This gives

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Hence, the number of square feet of outdoor carpet is 32 feet

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brainly.com/question/24487155

8 0
2 years ago
In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent (Pew Research, June 5, 2014). An independe
enot [183]

Answer:

a)

n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2, in which z is related to the confidence level.

b) A sample size of 991 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent

This means that \pi = 0.16

a. What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.03 (round up to the next whole number).

This is n for which M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = z\sqrt{\frac{0.16*0.84}{n}}

0.03\sqrt{n} = z\sqrt{0.16*0.84}

\sqrt{n} = \frac{z\sqrt{0.16*0.84}}{0.03}

(\sqrt{n})^2 = (\frac{z\sqrt{0.16*0.84}}{0.03})^2

n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2, in which z is related to the confidence level.

Question b:

99% confidence level,

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2

n = (\frac{2.575\sqrt{0.16*0.84}}{0.03})^2

n = 990.2

Rounding up

A sample size of 991 is needed.

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3 years ago
The ratio of pencils to pens is 4 to 6. If there are 24 pencils in the classroom, how many pens are there?
o-na [289]

Answer:36

Step-by-step explanation:

7 0
3 years ago
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