1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Volgvan
3 years ago
8

Please need help fast. Look at the pictures.

Mathematics
1 answer:
Leya [2.2K]3 years ago
5 0
It will definitely be a positive
You might be interested in
A right circular cylinder has a base radius of 56 mm and a height of 128 mm. What is its volume in cubic centimeters? Round the
anzhelika [568]

Answer:

V = 1261 mm2

Step-by-step explanation:

Hello

V = Pi*(r^2)*h

V = Pi*([56]^2)*(128=

V = 1261 mm2

Best regards

4 0
2 years ago
Tricia has $37.25 in her account. Which shows the amount she will have left after she writes a check for $23.99?
aliya0001 [1]
C :) brainiest? This is correct because I did the math lol
4 0
3 years ago
joe weighs 20lbs.less yhantwice jeffs weight.if jeff would gain 10lbs.,then together they wouldweigh 250lbs. how much does each
masya89 [10]
So,

Let x represent Joe's weight and y represent Jeff's weight.

"Joe weighs 20 lbs. less than twice Jeff's weight."
x = 2y - 20

"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
(y + 10) + x = 250

We now have our two open sentences.
x = 2y - 20
(y + 10) + x = 250

Get rid of parentheses.
x = 2y - 20
x + y + 10 = 250

We will use Elimination by Substitution.
2y - 20 + y + 10 = 250

Collect Like Terms.
3y - 10 = 250

Add 10 to both sides.
3y = 260

Divide both sides by 3.
Jeff's\ weight = 86 \frac{2}{3} \ lbs.

Substitute again.
x = 2(86 \frac{2}{3} )-20

Multiply.
x = 173 \frac{1}{3} -20

Subtract.
Joe's\ weight = 153 \frac{1}{3}\ lbs.

Check.

"Joe weighs 20 lbs. less than twice Jeff's weight."
Jeff's weight times two is 173 and one-third.
20 lbs. less than that is 153 and one-third lbs. Check.

"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
86 and two-thirds + 10 = 96 and two-thirds.
96 and two-thirds + 153 and one-third equals 250 lbs. Check.

Joe's\ weight\ is\ 153 \frac{1}{3} \ lbs.
Jeff's\ weight\ is\ 86 \frac{2}{3} \ lbs.
3 0
3 years ago
The height, h, of the equilateral triangle is given by h =5cotΘ, where Θ is 30 degrees. Can someone help me with this? I don't u
Hoochie [10]

You don't even need the picture to solve this one.

You said that      h = 5 cot(Θ) ,    and you said that  Θ  is 30 degrees.
All you need now is to find the cotangent of  Θ, plop that into the equation,
and the solution practically jumps off the paper into your lap.

To find the cotangent of 30 degrees, you can use a calculator, look it up
in a book, read it off of a slide rule if you have one, draw a picture of a
30-60-90 right triangle etc.  You'll find that the cotangent of 30 degrees
is  √3 .  That's about 1.732 .

So your equation is    h = 5 (1.732)  =  <em>8.66  </em>(rounded)

Apparently, somebody gave you the equation, and asked you to find 'h'.
Once you had the equation, you didn't even need to know that  'h'  has
anything to do with a triangle.


5 0
2 years ago
What is the answer to 89x87
MissTica

Answer: 89 x 87 =7,743

Step-by-step explanation:

8 0
2 years ago
Other questions:
  • Rewrite 3 1 over 5<br> as a mixed number?
    6·2 answers
  • Julius went on a volunteer trip to Central
    14·1 answer
  • Find the value of x.
    7·1 answer
  • I need help on this!!
    7·2 answers
  • What is 6 1/4 written as a decimal? Please help me I am very confused.
    12·2 answers
  • PLEASE HELP ME ALSO LOOK
    7·1 answer
  • Write in point slope form the equation of a line that has the slope of -4 and the passes
    6·1 answer
  • Help me please i need this ASAP!!!!
    15·1 answer
  • Simplify the expression please help ASAP
    10·1 answer
  • Jo and Val are a couple. Jo's monthly net earnings are $4000, and Val's are $6000. Following the 80/20 rule, how much should the
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!