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3 years ago

Please need help fast. Look at the pictures.

Mathematics

1 answer:

Leya [2.2K]3 years ago

5 0

It will definitely be a positive

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Exams are approaching and Helen is allocating time to studying for exams. She feels that with the appropriate amount of studying

svp [43]

Answer: 0.05

Step-by-step explanation:

Let M = Event of getting an A in Marketing class.

S = Event of getting an A in Spanish class,

i.e. P(M) = 0.80 , P(S) = 0.60 and P(M∩S)=0.45

Required probability = P(neither M nor S)

= P(M'∩S')

= P(M∪S)' [∵P(A'∩B')=P(A∪B)']

=1- P(M∪S) [∵P(A')=1-P(A)]

= 1- (P(M)+P(S)- P(M∩S)) [∵P(A∪B)=P(A)+P(B)-P(A∩B)]

= 1- (0.80+0.60-0.45)

= 1- 0.95

= 0.05

hence, the probability that Helen does not get an A in either class= 0.05

3 0

3 years ago

Which list shows all the factors of 36?

mina [271]

Answer:

Step-by-step explanation:

I'm too lazy to explain but if you want me to I will

8 0

3 years ago

HI is it posible to give me som anser for matematic

sergiy2304 [10]

Answer:

what type

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is 6% of 90? Helpp

Aloiza [94]

Answer:

Step-by-step explanation:

6/100 = x/90

6×90=540

540/100=54

8 0

3 years ago

You are to take a multiple-choice exam consisting of 64 questions with 5 possible responses to each question. Suppose that you h

stepan [7]

Answer:

(a) The expected score is 12.8

(b) The standard deviation is 3.2 and variance is 10.24

Step-by-step explanation:

Consider the provided information.

You are to take a multiple-choice exam consisting of 64 questions with 5 possible responses to each question.

Here n=64 p=1/5 and q=1-1/5=4/5

Part (a) we need to find the expected score on the exam.

Expected = np

Expected score = number of questions × P(right)

$Score = 64 \times \frac{1}{5} = 12.8$

Hence, the expected score is 12.8

Part (b) Compute the variance and standard deviation of x.

Standard Deviation: $\sigma =\sqrt{npq}$

Now calculate the standard deviation as shown:

$\sigma =\sqrt{64\times \frac{1}{5}\times \frac{4}{5}}$

$\sigma =\sqrt{\frac{256}{25}}$

$\sigma =\frac{16}{5}=3.2$

Variance: $\sigma^2 =npq$

$\sigma^2 =64\times \frac{1}{5}\times \frac{4}{5}$

$\sigma^2 =\frac{256}{25}$

$\sigma^2 =10.24$

Hence, the standard deviation is 3.2 and variance is 10.24

5 0

3 years ago