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Damm [24]
3 years ago
9

Which relation is a function?:)

Mathematics
1 answer:
pochemuha3 years ago
6 0
A is the answer......
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1/2 of a bowl of cereal is divided equally between 4 bowls. how much cereal is in each bowl
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1/16 of the cereal is in each bowl

Step-by-step explanation:

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What is the factored form of the polynomial? x2 − 12x + 27?
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A scientist has 100 milligrams of a radioactive element. The amount of radioactive element remaining after t days can be determi
grandymaker [24]
The mass of the first shipment at time t is
m_{1}=100( \frac{1}{2} )^{ \frac{t}{10}}

The mass of the second shipment at time t is
m_{2}=100( \frac{1}{2} )^{ \frac{t-3}{10} }

At time t, the ratio of m₁ to m₂ is
\frac{m_{1}}{m_{2}} = \frac{100}{100}. \frac{(1/2)^{t/10}}{(1/2)^{(t-3)/10}} \\ =  \frac{(1/2)^{t/10}}{(1/2)^{t/10}}. \frac{1}{(1/2)^{-3/10}} \\ = (1/2)^{3/10} \\ = 0.8123

Therefore as a percentage,
\frac{m_{1}}{m_{2}} =100*0.8123 = 81.23 \%

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4 0
4 years ago
The mass, m grams, of a radioactive substance, present at time t days after first being observed, is given by the formula m=24e^
Reika [66]

Answer:

(i) The value of<em> m</em> when t = 30 is 13.2

(ii) The value of <em>t</em> when the mass is half of its value at t=0 is 34.7

(iii) The rate of the mass when t=50 is -0.18            

Step-by-step explanation:

(i) The <em>m</em> value when t = 30 is:

m = 24e^{-0.02t} = 24e^{-0.02*30} = 13.2

Then, the value of<em> m</em> when t = 30 is 13.2

(ii) The value of the mass when t=0 is:

m_{0} = 24e^{-0.02t} = 24e^{-0.02*0} = 24    

Now, the value of <em>t </em>is:

ln(\frac{m_{0}/2}{24}) = -0.02t

t = -\frac{ln(\frac{24}{2*24})}{0.02} = 34.7

Hence, the value of <em>t</em> when the mass is half of its value at t=0 is 34.7

(iii) Finally, the rate at which the mass is decreasing when t=50 is:

\frac{dm}{dt} = \frac{d}{dt}(24e^{-0.02t}) = 24(e^{-0.02t})*(-0.02) = -0.48*                            (e^{-0.02*50}) = -0.18

Therefore, the rate of the mass when t=50 is -0.18.

I hope it helps you!                  

3 0
3 years ago
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