Question

A spider crawling across a table leaps onto a magazine blocking its path. The initial velocity of the spider is 0.870 m/s at an angle of 35.0° above the table, and it lands on the magazine 0.0770s after leaving the table. Ignore air resistance. How thick is the magazine? Express your answer in millimeters.

Answer 1

Answer:

Thickness of magazine = 9.42 mm.

Explanation:

Considering vertical motion of spider:-

Initial velocity, u =  0.870 sin 35 = 0.5 m/s

Acceleration , a = -9.81 m/s²

Time, t = 0.077 s

We have equation of motion s= ut + 0.5 at²

Substituting

   s= 0.5 x 0.077 - 0.5 x 9.81 x 0.077²

    s = 9.42 x 10⁻³ m = 9.42 mm

Thickness of magazine = 9.42 mm.