Explanation :
It is given that an oscillator makes 360 oscillations in 3 minutes.
(a) Using unitary method :
No. of vibrations in one minute is, 
So, no of vibrations in one minute is 120.
(b) Similarly,
3 minutes = 180 seconds
No of vibrations in one second is 
So, the no of vibrations in one second is 2.
(c) Time period of the wave is given by :
The time period of the wave is 0.5 s
(d) The no of vibation per second is called as its frequency.
Hence, this is the required solution.
Acceleration
due to gravity = 2.6m/s²
Length
of building = d = 88.3m
<span>Time
he needed before she hits the ground = ?
we can find the time by using the
formula;</span>
D =
1/2at²
Now
putting the value;
<span>88.3
= (1/2) a t</span>²<span>
88.3 = 1/2 x 23.6 x t</span>²
t² =
88.3 / 11.8
=
7.48
<span>t = 2.735 seconds
</span>
(a) The proton’s potential energy change is 3.6 x 10⁻¹⁸ J.
(b) The potential difference between the negative plate and a point midway between the plates is 11.25 V.
(c) The speed of the proton just before it hits the negative plate is 6.57 x 10⁴ m/s.
<h3>
Potential energy of the proton</h3>
U = qΔV
where;
- q is charge of the proton
- ΔV is potential difference
U = q(Ed)
U = (1.6 x 10⁻¹⁹)(1500 x 1.5 x 10⁻²)
U = 3.6 x 10⁻¹⁸ J
<h3>Potential difference between the negative plate and a point midway</h3>
ΔV = E(0.5d)
ΔV = 0.5Ed
ΔV = 0.5 (1500)(1.5 x 10⁻²)
ΔV = 11.25 V
<h3>Speed of the proton </h3>
U = ¹/₂mv²
U = mv²
v² = 2U/m
where;
- m is mass of proton = 1.67 x 10⁻²⁷ kg
v² = (2 x 3.6 x 10⁻¹⁸) / ( 1.67 x 10⁻²⁷)
v² = 4.311 x 10⁹
v = √(4.311 x 10⁹)
v = 6.57 x 10⁴ m/s
Thus, the proton’s potential energy change is 3.6 x 10⁻¹⁸ J.
The potential difference between the negative plate and a point midway between the plates is 11.25 V.
The speed of the proton just before it hits the negative plate is 6.57 x 10⁴ m/s.
Learn more about potential difference here: brainly.com/question/24142403
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A compass would work differently on the moon than the Earth because Earth's magnetic field is between 25,000 and 65,000 NanoTeslas. Whereas, the Moons magnetic field is about 2,500-6,500 and some parts of the moon have nonexistent magnetic fields.
Answer:
they are eletric and magnetic
Explanation:
