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3 years ago

9

A rectangular garden has a total area of 48 yards.Draw and label two possible rectangular gardens with diffrent side lenghts tha

t have the same area.

1 answer:

Vikki [24]3 years ago

7 0

Answer:

possible answers are

6x8

4x 12

2x 24

Step-by-step explanation:

You might be interested in

A bank loaned out $68,000, part of it at the rate of 13% per year and the rest at a rate of 5%per year. If the interest received

marin [14]

Answer: $31000 was loaned at 13%.

Step-by-step explanation:

Let x represent the amount loaned out at 13% interest rate.

Let y represent the amount loaned out at 5% interest rate.

The bank loaned out $68,000, part of it at the rate of 13% per year and the rest at a rate of 5%per year. It means that

x + y = 68000

The interest received made from $x in one year is

13/100 × x = 0.13x

The interest received made from $y in one year is

5/100 × x = 0.05y

If the interest received was $5880, it means that

0.13x + 0.05y = 5880- - - - - - - - - 1

Substituting x = 68000 - y into equation 1, it becomes

0.13(68000 - y) + 0.05y = 5880

8840 - 0.13y + 0.05y = 5880

- 0.13y + 0.05y = 5880 - 8840

- 0.08y = - 2960

y = - 2960/- 0.08

y = 37000

x = 68000 - y = 68000 - 37000

x = $31000

5 0

3 years ago

Rearrange the equation A = xy to solve for x.

mote1985 [20]

X = A/y
You divide the y from both sides
The y on the right cancels
On the left you have A/y = x

5 0

2 years ago

Which of the following represents the sum of the series? 6 8 10 12 14 16 18 20 22 24 26

stira [4]

The sum of the arithmetic series 6 8 10 12 14 16 18 20 22 24 26 is 176

<h3>How to determine the sum of the series?</h3>

The series is given as:

6 8 10 12 14 16 18 20 22 24 26

The above series is an arithmetic series with the following parameters:

First term, a = 6

Last term, L = 26

Number of terms, n = 11

The sum of the series is calculated using:

$S_n= \frac{n}{2} *(a + L)$

This gives

$S_n= \frac{11}{2} *(6 + 26)$

Evaluate

$S_{11} = 176$

Hence, the sum of the arithmetic series 6 8 10 12 14 16 18 20 22 24 26 is 176

Read more about arithmetic series at:

brainly.com/question/6561461

#SPJ4

7 0

2 years ago

The population of a town has grown at an annual rate of 2.7%. How long does it take for it’s population of 18,450 people to doub

charle [14.2K]

It would take 26 years.

The equation will be in the form y = a(1+r)ˣ, where a is the initial population, r is the growth rate as a decimal number, and x is the amount of time. Using our information we have

y = 18450(1+0.027)ˣ = 18450(1.027)ˣ

We want the population to be doubled; 18450*2 = 36900:
36900 = 18450(1.027)ˣ

Divide both sides by 18450:
36900/18450 = 18450(1.027)ˣ/18450
2 = 1.027ˣ

Using logarithms, we have
$\log_{1.027}2=x
\\
\\x=26.017$

3 0

2 years ago

A survey asks, "If the husband in a family wants children, but the wife decides that she does not want any children, is it all r

vodka [1.7K]

Answer:

a. The 99% confidence interval for the population proportion is (0.7872, 0.8610).

D. Yes, we can conclude that the population proportion exceeds 75% because 75% is below the lowest believable value of the confidence interval.

b. The 99% confidence interval would be wider than a 95% confidence interval.

As the confidence level increases, the width interval increases, as we are requiring more confidence with the same information (there is no new sample). This means that, to be more confident, the only way is to include more values in the interval.

Step-by-step explanation:

We have to calculate a 99% confidence interval for the proportion.

The sample proportion is p=0.8241.

$p=X/n=581/705=0.8241$

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.8241*0.1759}{705}}\\\\\\ \sigma_p=\sqrt{0.000206}=0.0143$

The critical z-value for a 99% confidence interval is z=2.5758.

The margin of error (MOE) can be calculated as:

$MOE=z\cdot \sigma_p=2.5758 \cdot 0.0143=0.0369$

Then, the lower and upper bounds of the confidence interval are:

$LL=p-z \cdot \sigma_p = 0.8241-0.0369=0.7872\\\\UL=p+z \cdot \sigma_p = 0.8241+0.0369=0.8610$

The 99% confidence interval for the population proportion is (0.7872, 0.8610).

We can conclude that there is, at least, 99% chances that the true proportion is higher than 0.7872. So there is at least 99% chances that the population proportion is higher than 0.75.

4 0

2 years ago