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Brums [2.3K]
3 years ago
11

In triangle ABC, the size of angle B is 5 times the size of angle A, and the size of angle C is 7 less than 4 times the size of

angle A
Mathematics
1 answer:
kipiarov [429]3 years ago
5 0
It sounds like everything is being described in reference to angle A, so a good starting point is to pick a variable to represent the measure of angle A. I'm going to use "a" for that.

Next, I'm going to take the verbal descriptions in the problem and "translate" them into "math language". They say angle B is 5 times angle A, so that means the measure of angle B is actually 5a. The size of angle C is 5 degrees less than 4 times the size of A, so that translates to 4a-5.

We now know the following:

Angle A: a
Angle B: 5a
Angle C: 4a-5

Now, to find the value of a, we need to remember that all the angles in a triangle add up to 180 degrees.

So we have: a+5a+4a-5 = 180

We can solve that equation by combining like terms to get: 10a-5=180

We can add 5 to both sides: 10a =185

And divide by 10: a = 18.5

That tells us the measure of angle A! (It's 18.5 degrees). Now we can go back and find B by multiplying A by 5. We get 92.5 degrees for that.

Finally, we can find C by taking 4*18.5-5. We get 69 degrees for that.

One last thing-- let's check that they really do add up to 180! 69+92.5+18.5 = 180. Yep!

Hope that helps you!!
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Answer:

2x3x5=120

Step-by-step explanation:

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1 year ago
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MrMuchimi
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6 0
3 years ago
What is 6.8 to a fully simplified mixed number
Alisiya [41]
6.8

= 6 + 0.8

= 6 + 8/10 (simplifying...)

= 6 + (8 : 2)/(10 : 2)

= 6 + 4/5

= 6 4/5 <----- this is the answer.

I hope this helps. =)
6 0
2 years ago
a chinchilla weighs 2 pounds its weight is 1/8 the weight of a koala write an expression and solve it to show how much the koala
Wittaler [7]
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So x * 1/8 = 2

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So you can just divide both sides by 1/8 first.

x * 1/8 = 2

/ 1/8       / 1/8

Or,

x *1/8 * 8/1 = 2 * 8/1

x = 16

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6 0
3 years ago
The box plots below show attendance at a local movie theater and high school basketball games:
Firdavs [7]

Assume that the data for both movies and basketball games are normally distributed.
Therefore, the median and the mean are assumed equal.
The standard deviation, σ, is related to the interquartile range by
IQR = 1.35

From the data, we can say the following:

Movies:
Range = 150 - 60 = 90 (approx)
Q1 = 62 (approx), first quartile
Q3 = 120 (approx), third quartlie
Q2 (median) = 90 (approx)
IQR = Q3 - Q1 = 58
σ = IQR/1.35 = 58/1.35 = 43

Basketball:
Range = 150 - 90 = 60 approx
Q1 = 95 (approx)
Q3 = 145 (approx)
Q2 = 125 (approx)
IQR = 145 - 95 = 50
σ = 50/1.35 = 37

Test the given answers.
A. The IQRs are approximately equal, so they are not good measures of spread. This is not a good answer.
B. The std. deviation is a better measure of spread for basketball. This is not a good answer.
C. IQR is not a better measure of spread for basketball games. This is not a good answer.
D. The standard deviation is a good measure of spread for both movies and basketball. This is the best answer.

Answer: D
7 0
2 years ago
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