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3 years ago

Find the sum and product of the zeros 2 X square + X - 5 = 0

Mathematics

2 answers:

Leni [432]3 years ago

6 0

Answer:

x=2

Step-by-step explanation:

2x+x- 5 =0

valentinak56 [21]3 years ago

3 0

X=2 hope this helps

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Which description is true about pre-image ABC and image A′B′C′ ?

scoray [572]

Answer:

Option (C)

Step-by-step explanation:

From the graph attached,

In ΔABC and ΔA'B'C',

∠A ≅ ∠A'

∠B ≅ ∠B'

Therefore, ΔABC ~ ΔA'B'C'

Corresponding sides of these triangles will be proportional.

$\frac{\text{AB}}{\text{A'B'}}=\frac{\text{BC}}{\text{B'C'}}=\frac{\text{AC}}{\text{A'C'}}=\frac{2}{6}$

Therefore, ratio of the sides, AC : A'C' = 1 : 3 shows that image triangle A'B'C' is a dilated form of pre-image ABC with a scale factor of 3.

Option (C) will be the correct option.

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3 years ago

The edge of each cube used to build this rectangular prism is 13

kolbaska11 [484]

Answer:

$\frac{3}{3} * \frac{2}{3} *\frac{3}{3} =\frac{2}{3} \ in^3$

====================================================

Step-by-step explanation:

The question is missing the attached figure.

The edge of each cube used to build this rectangular prism is 1/3 inch long. Based on the attached figure.

the volume of the prism = length × height × width

length = $3 * \frac{1}{3} = \frac{3}{3}$

height = $3 * \frac{1}{3} = \frac{3}{3}$

width = $2 * \frac{1}{3}= \frac{2}{3}$

So the volume of the prism = $\frac{3}{3} *\frac{3}{3} *\frac{2}{3} =\frac{2}{3} \ in^{3}$

∴ The equation that shows the volume of the prism, in cubic inches

= $\frac{3}{3} * \frac{2}{3} *\frac{3}{3} =\frac{2}{3} \ in^3$

8 0

3 years ago

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Which equation is equivalent to log3(x+5)=2

Lisa [10]

In exponential form: 10^2=3(x+5)
If we were to solve, x=85/3

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3 years ago

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Add. Simplify the answer to lowest terms before entering the numerator and denominator in their boxes. 11/16 + 3/16

myrzilka [38]

Answer:

The answer is 7/8.

Step-by-step explanation:

If you add 11/16 to 3/16, you'll get 14/16. 14/16 has two numbers that are divisible by 2, so when you divide 14/16 by 2 you'll get 7/8 which is 14/16 in a simplified form. 7 is prime and you can't divide it down any more, but 8 i'snt the same way. The rule is, whatever you do to one side, you have to do to the other. You can divide 8, but not 7; therefore, you cannot simplify the fraction any further.

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3 years ago

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What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?

Ipatiy [6.2K]

Answer:

$x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}$

Step-by-step explanation:

$2x^2 - 10x - 3 = 0 \\\\a = 2 \ , b = - 10 \ , \ c = - 3 \\\\x = \frac{-b^2\ \pm \ \sqrt{b^2 - 4ac}}{2a}\\\\x = \frac{10 \ \pm \sqrt{(-10)^2 - ( 4 \times 2 \times -3)} }{2 \times 2}\\\\x = \frac{10 \ \pm \sqrt{(100 - ( -24 )} }{4}\\\\x = \frac{10 \ \pm \sqrt{(100 + 24 } }{4}\\\\x = \frac{ 10 \ \pm \sqrt{124}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{4 \times 31}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{2^2 \times 31}}{4}\\\\x = \frac{ 10 \ \pm2 \sqrt{31}}{4}\\\\x = \frac{ 5 \ \pm\sqrt{31}}{2}\\\\$

$x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}$

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2 years ago

Find the sum and product of the zeros 2 X square + X - 5 = 0​

Find the sum and product of the zeros 2 X square + X - 5 = 0