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podryga [215]
3 years ago
14

_______ is the formation of alcohol from sugar.

Chemistry
2 answers:
anzhelika [568]3 years ago
8 0

Answer: d. Alcoholic fermentation

Explanation:

The alcohol fermentation is a process in which the sugars like fructose, sucrose and glucose are transformed into alcohol and carbon dioxide by the activity of microorganisms or fungi. It is a biological process. This process takes place in the absence of oxygen. In the absence of oxygen this process is called as anaerobic process. The alcohol produced after this process is used for making beverages, bread and fuel.

Katarina [22]3 years ago
7 0
The best and most correct answer among the choices provided by the question is the fourth choice "alcoholic fermentation"

Ethanol fermentation<span>, also called </span>alcoholic fermentation<span>, is a biological process which converts sugars such as glucose, fructose, and sucrose into cellular energy, producing </span>ethanol<span> and carbon dioxide as a side-effect.</span>

I hope my answer has come to your help. God bless and have a nice day ahead!
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(20 points) i) An absorption intensity of 1.00 (in arbitrary units) is observed for the maximum peak of the 1:2:1 triplet of the
laiz [17]

Answer:

Concentration of ethanol required =  48.476 M

Explanation:

Given that:

the absorption intensity = 1.00

Molarity of ethanol = 1M

NMR instrument used = 160 MHz

Temperature used = 300 K

The required concentration of ethanol can be determined as follows:

=  ( 1 \ M \times \dfrac{160\ MHz }{450 \ MHz}) \times \dfrac{300 \ K}{2.2\ K}

=  ( 1 \ M \times 0.3555 ) \times136.36}

= 48.476 M

5 0
3 years ago
Find the value of the solubility product ksp for a saturated solution of mercury bromide, hgbr2, using the solubility of mercury
kondaur [170]
When the reaction equation is:

HgBr2(s) ↔ Hg2+(aq)   +   2Br-(aq)

So Ksp expression = [Hg2+] [Br-]^2

assume the solubility S = X = 2.66 x 10^-7 M 

and from the reaction equation :

we can see that [Hg2+] = X

and the [Br-] = 2 X

so by substitution in Ksp formula will can get the Ksp value:

∴ Ksp = X * (2X)^2

       = 2.66 x 10^-7 * (2*2.66 x 10^-7)^2

       = 7.53 x 10^-20
7 0
3 years ago
Hello tell me how to find this <br><br>k+o2&gt;&gt;k2o its o ok
umka2103 [35]

Explanation:

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4 0
2 years ago
how many grams of calcium oxide are producer from the decomposition of 125 grams of calcium carbonate
Dmitrij [34]

70.0 g. The decomposition of 125 g CaCO3 produces 700 g CaO.

MM = 100.09 56.08

CaCO3 → CaO + CO2

Mass 125 g

a) Moles of CaCO3 = 125 g CaCO3 x (1 mol CaCO3/100.09 g CaCO3)

= 1.249 mol CaCO3

b) Moles of CaO = 1.249 mol CaCO3 x (1 mol CaO/1 mol CaCO3)

= 1.249 mol CaO

c) Mass of CaO = 1.249 mol CaO x (56.08 g CaO/1 mol CaO) = 70.0 g

7 0
3 years ago
Lithium bromide dissociates in water according to the following thermochemical equation: LiBr(s) → Li+ (aq) + Br– (aq) ΔH = –48.
madreJ [45]

Answer:

Final temperature of water is 48.3^{0}\textrm{C}

Explanation:

1 mol of LiBr releases 48.83 kJ of heat upon dissolution in water.

So, 2 moles of LiBr release (2\times 48.83)kJ or 97.66 kJ of heat upon dissolution in water.

This amount of heat is consumed by 1000.0 g of water. Hence temperature of water will increase.

Let's say final temperature of water is t^{0}\textrm{C}.

So, change in temperature (\Delta T) of water is (t-25)^{0}\textrm{C} or (t-25) K

Heat capacity (C) of water is 4.184\frac{J}{g.K}

Hence, m_{water}\times C_{water}\times \Delta T_{water}=97.66\times 10^{3}J

where m is mass

So, (1000.0g)\times (4.184\frac{J}{g.K})\times (t-25)K=97.66\times 10^{3}J

or, t=48.3

Hence final temperature of water is 48.3^{0}\textrm{C}

3 0
3 years ago
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