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mrs_skeptik [129]
2 years ago
8

If I have 7.7 moles of gas at a pressure of 9.12 kPa and a temperature of 56 °C,

Chemistry
1 answer:
Paul [167]2 years ago
6 0

Answer:

C

Explanation:

n= 7.7mol

P= 9120pa

T = 329.15K

PV=nRT

V= nRT/P

V= (7.7×8.314×329.15)/9120

V= 2.308meter cubic

V= 2308L

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Read 2 more answers
A sample of sulfur hexafluoride gas occupies a volume of 5.10 L at 198 ºC. Assuming that the pressure remains constant, what tem
Ludmilka [50]

Answer:

When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K

Explanation:

Step 1: Data given

A sample of sulfur hexafluoride gas occupies a volume of 5.10 L

Temperature = 198 °C = 471 K

The volume will be reduced to 2.50 L

Step 2 Calculate the new temperature via Charles' law

V1/T2 = V2/T2

⇒with V1 = the initial volume of sulfur hexafluoride gas = 5.10 L

⇒with T1 = the initial temperature of sulfur hexafluoride gas = 471 K

⇒with V2 = the reduced volume of the gas = 2.50 L

⇒with T2 = the new temperature = TO BE DETERMINED

5.10 L / 471 K = 2.50 L / T2

T2 = 2.50 L / (5.10 L / 471 K)

T2 = 230.9 K = -42.1

When the volume will be reduced to 2.50 L, the temperature will be reduced to a temperature of 230.9K

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