Answer:
Q = - 8501.99 j
Explanation:
Given data:
Specific heat of Al = 0.902 j/g.°C
Heat lost = ?
Mass of sample = 23.984 g
Initial temperature = 415°C
Final temperature = 22°C
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 22°C - 415°C
ΔT = -393°C
Q = m.c. ΔT
Q = 23.984 g× 0.902 j/g.°C × -393°C
Q = - 8501.99 j
We are given with a compound, Zinc (Zn) having a 1.7 x 10
^23 atoms. We are tasked to solve for it's corresponding mass in g. We need to
find first the molecular weight of Zinc, that is
Zn= 65.38 g/mol
Not that 1 mol=6.022x10^{23} atoms, hence,
1.7 x 10 ^23 atoms x 1 mol/6.022x10^{23} atoms x65.38
g/ 1mol
=18.456 g of Zn
Therefore, the mass of Zinc 18.456 g
250gTi x (1mol/47.87 [molar mass]) =5.22247 moles
A. Conducting a drug experiment which will harm lab rats
Explanation:
An enzyme inhibitor is a molecule that binds to an enzyme and decreases its activity. ... Since blocking an enzyme's activity can kill a pathogen or correct a metabolic imbalance, many drugs are enzyme inhibitors. They are also used in pesticides.
