Do you see -8x?
Take half of -8 and square it.
So, (-8)/2 = -4.
(-4)^2 = 16
Now add 16 to both sides.
Answer:
x = 4 and -10
Step-by-step explanation:
Given the equation
x²+6x-40= 0
The common factors to use for the factorisation are +10 and -4
x²+(10x-4x)-40=0
(x²+10x)-(4x-40) = 0
x(x+10)-4(x+10) = 0
(x-4)(x+10) = 0
x-4 =0 and x+10 = 0
x = 4 and x = -10
Answer:
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Step-by-step explanation:
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The solution of simultaneous equations is x=4 and y = -1.
<h3>What are
Simultaneous equations?</h3>
Simultaneous equations are two or more algebraic equations with the same unknown variables and the same value of the variables satisfies all such equations.
We can solve simultaneous equations by various methods. here we will solve it by elimination method.
Here we have two simultaneous equations
3x -2y = 14 --- (i)
and 4x + 3y = 13---(ii)
Now multiplying (i) by 3 and (ii) by 2 we get
9x -6y = 42 and 8x + 6y = 26.
Now adding both we get
17x = 68 ⇒ x = 68/17 ⇒ x = 4.
Substituting the value of x in (i), we get
3*4 - 2y = 14 ⇒ -2y = 14-12 = 2 = -2/2 ⇒ y = -1.
Therefore, the values of x and y are 4 and -1 respectively .
To know more about simultaneous equations, visit
brainly.com/question/16863577
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<u>NOTE</u> : The question given here is not complete. The complete question is given below.
Question: What is the solution of the simultaneous equations 3x- 2y= 14 and 4x+ 3y= 13?.
