Molality of Mg²⁺ ions = 0.0548
Molality of SO₄²⁻ ions = 0.0293
<h3>Further explanation</h3>
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. Concentration shows the amount of solute in a unit of the amount of solvent.
Molality (m)
Molality shows how many moles are dissolved in every 1000 grams of solvent.
m = Molality
n = number of moles of solute
p = solvent mass (grams)
To find the molality of these ions we determine the value of solvents and dissolved moles (moles of magnesium ions and sulfate ions)
We use the calculation base of 1 Liter of solution so that the mass of the seawater.
seawater mass: volume x density
seawater mass: 1000 ml (1 L) x 1,022 g / mL
seawater mass: 1022 grams = 1,022 kg
then the total mass of ions in solution =
35,067 gr / kg x 1,022 kg = 35,838 gr
Solvent mass = seawater mass - ion mass
mass of the solvent = 1022 - 35,838
solvent mass = 986,162 grams
concentration = 54.14 mM = 54.10⁻³ M
because it is counted in 1 liter of solution then Mg²⁺ = 54.10⁻³ mole ion
m = 0.0548
concentration = 28.93 mM = 28.93.10⁻³ M
mole SO₄²⁻ = 28.93.10⁻³
m = 0.0293
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Keywords: molal, seawater, density